Forms Data Controls :: Create An Instance Of A TextBox In A GridView When Using FindControl?
Dec 28, 2010
In my GridView I use FindControl/<FooterTemplate> with a TextBox that you can enter an integer with a comma
into the TextBox, because I create an instance of the Textbox first and then remove the comma out of the integer before the TextBox is used to update the table in the database.
However once the data is in the table and displayed in the GridView if you try to change the integer and use a comma in the GridView you cannot because FindControl/<EditItemTemplate> will not create an instance for you to remove the comma from the integer before it updates the table because FindControl/<EditItemTemplate> doesn't allow you to create an instance of the TextBox first, instead when you try to use the instance that looks like was created it gives an error stating:
Object reference not set to an instance of an object.
So the question is:
HOw do you create an instance of a TextBox in a GridView when using FindControl/<EditItemTemplate>?
<form id="form1" runat="server">
<div>
</div>
<asp:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server">
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Mar 17, 2011
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Code Behind
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Iwrite this code but I get
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[code]
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[Code]....
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[Code]....
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[Code]....
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Object reference not set to an instance of an object.
Description:
An unhandled exception occurred during the execution of the current web request. review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.NullReferenceException: Object reference not set to an instance of an object.
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[Code]....
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