MVC :: MSChart In Partial View?
Jan 29, 2010
Got the MSChart working fine in a standard view, but I'm trying to put them on partial views that I'm then loading using jQuery tabs.
Problem is if you try to put the Chart on a partial, it moans about System.Web.UI.DataVisualization, saying it can't find it, no problem on a standard view though.
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Similar Messages:
Feb 26, 2010
using Mschart on my MVC project,when i use the first index page of project to render for the partial view name index2 the code is
<% Html.RenderPartial("Index2"); %>
But when i run it the error is occur which the message is
CS0029: Cannot implicitly convert type 'ASP.views_home_index2_ascx' to 'System.Web.UI.Page'
-it said that the problem line of code is
: // Render chart control
Line 52: Chart2.Page = this;
[code]...
But when i put all of code in Index2.ascx to the index.aspx and not to render the partial view it work fine
Code of Index2.ascx is
<%
System.Web.UI.DataVisualization.Charting.Chart Chart2 = new System.Web.UI.DataVisualization.Charting.Chart();
Chart2.Width = 412;
Chart2.Height = 296;
[code]...
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Sep 8, 2010
Members view (index) that lists members that users can select to show a partial view in the same view with details for the selected memberUses jquery (Ajax.ActionLink) to call a partial view method in the members controller to then load the members detail sectionWorks fine up to here....but I'd like to load the partial view with "member" details for a default or random member on initial load -- ie not through the Actionlink selectionHow do I invoke the partial view method on the initial load?
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Jan 27, 2011
Let's say there is a textbox and a dropdownlist in mainview page, these two values are used by three partial views as well. when I use Html.RenderAction to post action to those three partial views, how to pass these two values to those partial views and in those views how to get these two values as a part of a object to send to database.
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Feb 16, 2011
I need to display an error message in the view when there's an error in rendering the partial view in that View.
How can i handle the exception while rendering partial view and display the error message in the view?
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Dec 29, 2010
've created a Search partial view and it works, except for my view model. What i mean is, the partial view sends a string to my ActionResult Method, but only a string, that is not related to the view model that the partial view is built in. If i tell my ActionResult method to receive the view model in which the partial view is built in, it always tells me that i have null values. Here's my code This is my partial view:
[Code]....
Now here is my Model in my MoviesSearch view model:
[Code]....
Now the actual MoviesSearchViewModel
[Code]....
Inside my Search controller i have this
[Code]....
And then i have this:
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Mar 6, 2011
I have added a jquery datepicker on my MVC view. This view has a partial view. I need to filter my partial view based on the datepicker's selected date. I need to show buttons on partial view based on the date.
I have added partial view like this:
div id="dvGames" class="cornerdate1"> % Html.RenderPartial("Partial3"); %>
/div>
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Feb 11, 2011
I have a partial view that is rendered on a view. That partial view has textboxes in it. The user can enter values into them.
I need to put all the values from the textboxes in my partial view into an array, and then give the view (the parent page rendering that partial view) access to that array.
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Oct 19, 2010
I am trying to use a partial view for a file upload in a Create View.
Here is my partial view, I removed the submit button, as the view it is rendered in, should activat the form post:
@model dynamic
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Jan 27, 2010
Can i create a partial view and a controller that will feed data to the view, and if i render that partial in a Master page, the Data will show on whatever URL i am?
Or is there another way of showing content from database on every page(view)?
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May 3, 2010
making my first steps with asp.net mvc and I actually create a (very) small website.I have 1 controller : TasksController1 view : Tasks/Index.aspx1 Partial View : Tasks/AvailableSorting.ascx In my controller I have 2 methods :
[Code]....
In my Tasks/Index.aspx, I add my partial view (<% Html.RenderPartial("AvaliableSorting"); %>)
That sounds simple. But, It just doesn't work : the Index return a list of Task and the parial view (should) return a list of string.The index.aspx works perfectly, but the partial view doesn't get the right model ! he gets the model of the Index page (list of Task).
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Oct 27, 2010
"When a partial view is instantiated, it gets its own copy of the ViewDataDictionary object that is available to the parent view. The partial view therefore has access to the data of the parent view. However, if the partial view updates the data, those updates affect only the partial view's ViewData object. The parent view's data is not changed."Is there a common way around this? For instance I have a View containing two Partial Views (User Controls) that source the same data from the Parents ViewData. The first Partial View is able to update (add/delete) certain data from the Parents View Data, however the second Partial View sources the same data but obviously isn't reflecting the changes owing to the above MSDN statement.
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Nov 22, 2010
I would like to add a partial view to my view page
The view page contain a mode name "<IEnumerable<JvTake1.Models.VortN>>
And the partial view contain a model name "<IEnumerable<JvTake1.Models.VideoL>>"
So, theoretically I think they were suppose to work together but no Can any one guide me how to make it happen?
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Nov 10, 2010
I have a view that displays all the records of my Roles table. I want to be able to click a Role record and have a list of users that pertain to that role displayed to the right of the Roles list. I'm sure I need to use a view model for this so I can get two sets of models in one view, but I'm not sure how to set up the view model.
Controller code:
[Code]....
Repository (userRep) code:
[Code]....
I can just as easily get the full user list with return db.Users;
So what method needs added to my repository and how should my view model look?
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Mar 4, 2011
I am new to MVC coding, and currently try to migrate a legacy ASP.NET Web Form application into MVC. In Web Form I have several user controls, for example one control will be responsible to display a tree structure and user can select category from tree and do next step. In Web Form implemenation user control just raises the event to hosting web form, from there web form takes data to do whatever it needs to do.
While in MVC, I created correspodning partial view to display category data in a tree structure, I can display it, select node of tree without problem. But how can I let the hosting page/view know that some event is raisen from the partial view? What shall be the correct concept to handle this type of requirement?
There are different pages to reuse the same partial view, for example I may have following scenarios:
A category selection partial view in a user input page to trigger the input fields (quatity, date/time) to display and submit order. A category selection partial view in an admin page to trigger the display of invoice price, listing price and so on.
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Jan 10, 2011
I have a partial view that has only a dropdown, i have called this partial view from a view. I can able to pass the model to this partial view and it renders successfully. However when some user selects a particular text from the dropdown, the corresponding value should be passed to view and it should be displayed in the label in view.
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Oct 27, 2010
I am totally a new bee in asp.net mvc. Let me now explain my issue. I have a strongly typed view which inherits from a view model Document. I want to have a partial view in that view itself. My code for this purpose is :
<%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<HexsolveMVC.Models.Document>" %>
<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
DetailsDocumentTemplate
</asp:Content>
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">
<div>
<div>
<div>
2.4</div>
<div>
Published</div>
<h1>
Document Title: <span>
<%=Model.DocTitle %></span><span><a href="#">[ Edit ]</a></span></h1>
<ul>
<li>
<label>
<span>*</span>Created Date:</label>
<span>
<%= Model.DocCreatedDate%></span></li>
<li>
<label>
Status:</label>
<span>.................................
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Nov 1, 2010
I would like to create one view for my CRUD actions. The view contains 3 basic DIV updatetargets ("search form", "search result listing" and "action" (would be create,detail,edit,delete). Basic flow would be: "Search" updates the "Search Result Listing", click on CRUD actions in listing would show partial view in "action".
how do I call to refresh the "Listing" after I do any add/update/delete without having user click search again?
Index:
[Code]....
Result Listing:
[Code]....
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Feb 17, 2011
How can I use use an actionResult to return both a view and a partial view. Actually in case of an ajax request it should send a partial view else it should send a view.
public ActionResult Test(string Name ="", DateTime? Date= null, string sex="" )
{
myModel model = new myModel(Name, Date, Sex);
if(IsAjaxRequest)
return PartialView("partialView", model)
else
return View(model);
}
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Dec 27, 2010
i need to do something like this :
i have a partial view and i can go to it like this :
/home/GetMovies?partial=true
this return a STRING with a movie inside
some times i want to return this string inside other view
(lets say i want to put the string movie thing inside full html view and not just the movie string )
so im doing it like this:
/home/GetMovies?partial=false
how the seriver side should look like ?
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May 5, 2010
I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed.How do I do I pass the model to this strongly typed view?I tried something like
public ActionResult Test()
{
MyData = new Data();
MyData.One = 1;
return View("Test",MyData)
}
In my TestView
<% Html.RenderPartial("PartialView",Model); %>
This give me a stackoverflow exception. So I am not sure how to pass it on. Of course I don't want to make the test view strongly typed if possible as what happens if I had like 10 strongly typed partial views in that view I would need like some sort of wrapper.
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Feb 22, 2011
I'm rather liking this MVC3 and Razor way of working and I'm learning the ropes. I was wondering, can I create a partial view and pull it into another view in the following scenario:I have a "Person" model and an "Address" model. The Person contains name, phone number etc and each person has an address. I've created my Person "Create" view and that works fine but I now want to pull in my "Address" partial view to it.
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Feb 9, 2011
I have a textbox in a view .when user enters a code in textbox and press a button,in callback , I want to show a list below that which shows some information searched by that code in a table.
I think I should use partial view but I don't know how?
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Aug 4, 2010
I have a strongly typed partial view named "Address". This partial view contains 'input' fields associated to an Address model class. I want to render it twice in the same view because the user must input the Home address and the Business address.
I have problem with client validation because of the ID of the 'input' rendered is not unique.
Is there a way to set a kind of scope so the id of the 'input' for each partial view has a unique ID that can be recognized by the modelBinder , so that my page post back can correctly organize data into respective address type?
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Mar 27, 2011
I have an Index view that shows a list of employees and a Create partial view with a form and submit button to create employees. In the Index view, I have:
@{Html.RenderAction("Create");}
A user sees a blank form to create employees and a list of employees. After the user has typed data in the form and clicked the submit button, the form should become blank and the list of employees should be refreshed, showing employees plus the new employee.
The problem is I don't know what to return from the Create action:
public ActionResult Create(Employee employee)
{
return ???
}
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