Show Two Properties In One Column Of Grid View C#?
Feb 7, 2011
I have class Person, having two properties First Name and Last Name, if I set array of person as Data Source to GridView how can I show both First Name and Last Name in one column?/
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Apr 20, 2010
I have gridview and want to show datalist in grid view view column on click of linkbutton show.
[Code]....
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May 27, 2010
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Feb 2, 2011
I have an entity "Order", which contains a set of states. Every state has date and name.
I want show grid with all orders and in grid one column with last state of order. But I dont understand how to do it.
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Jun 30, 2010
I'm getting some Xml back from a service. I would like it to be the datasource of a grid view on my aspx page. Here is a sample of the Xml
<?xml version="1.0" encoding="utf-16" ?>
<ArrayOfTripTollCompleteDC xmlns:xsi=[URL]"
xmlns:xsd=[URL]>
<TripTollCompleteDC>
<TripTollId>5</TripTollId>
<DMSLaneModeID xsi:nil="true" />
<HOVOnly>false</HOVOnly>
<CreateDateTime>2010-06-07T15:54:01.023</CreateDateTime>
<ConfigVTMSDelaySeconds>5</ConfigVTMSDelaySeconds>
</TripTollCompleteDC>
and here is my code that parses the xml and tries to bind the grid. What am I missing here?
var retVal = service.GetTripDetailsByTripID(tripId);
var xmlTrips = XDocument.Parse(retVal);
var tripTolls =
from t in xmlTrips.Elements("TripTollCompleteDC")
select new {
TripTollId = (int)t.Element("TripTollId")
, DMSLaneModeID = (int?)t.Element("DMSLaneModeID")
, HOVOnly = (bool)t.Element("HOVOnly")
, CreateDateTime = (DateTime)t.Element("CreateDateTime")
, ConfigVTMSDelaySeconds = (int)t.Element("ConfigVTMSDelaySeconds")
};
grdTripDetails.DataSource = tripTolls;
grdTripDetails.DataBind();
I realize these are anonymous types. Is that a problem? I have verified the service is returning the Xml as stated above. Can anyone out there point me in the right direction? Just for completeness, here is the grid markup <asp:GridView runat="server" ID="grdTripDetails" />
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Jun 25, 2010
I have search for a long long time and could not find a solution to access to grid view's column properties. I have binded a grid view through this method, the bindGridView function will return a table with columns and rows.
The problem here is I cound not access to columns properties such as Grid_View.Columns.Count or Grid_View.Columns[0]."something". It seems like the grid_view does not have any column. But I can access to the Rows properties.
I have put this code within a (!IsPostBack) and set the AutoGenerateColumns to true?
I need to access to columns badly as I need t add additional column to the binded grid view.
[Code]....
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Jun 8, 2010
i have created a simple view, and display it into gridview.. i have successfully created view but it is not shown in grid view , it return nothing...
protected void Button3_Click(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(@"Data Source=.SQLEXPRESS;AttachDbFilename=E:
arenHDI-AJAX-TK-Calendar-CSApp_DataDatabase.mdf;Integrated Security=True;User Instance=True");
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da.Fill(ds);
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con.Close();
}
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Sep 15, 2010
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Jan 23, 2011
I have a gridview and in this grid one link button "view" is in each row
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Feb 22, 2010
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Aug 17, 2010
I have a GridView in ASP.Net 3.5. I added BoundFields as columns, set DataField and Header Text. Total I have 6 columns like that. Although I set "AllowSorting=True" in design view, when I run this page, all the columns didn't have hyper link that I can click on it and sort that particular column. I bind this column at code behind by using datatable.
gv.DataSource = dtDispatch
gv.DataBind()
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Feb 17, 2011
I am sorting the grid using DataView's "Sort" property. I am passing sort expression and the order in which the grid is to be sorted(ASC or DESC). But the problem is, since the column on which I am sorting the grid is listing the intergers, the sorting is happening as if it is a string. But I need integer sorting rather string sorting on that column.
The grid displays below as ascending order(string sorting)
55
77
8
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8
55
77
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Apr 14, 2010
I have a gridview which automatically adjusts with the dataset but i want to adjust he size a bit
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Mar 18, 2011
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Aug 19, 2010
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Aug 20, 2010
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Aug 22, 2010
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Apr 29, 2010
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Mar 10, 2011
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Jun 24, 2010
I got this code which bind a datatable to a grid view. After the binding, i wanted to add additional column to the right of the grid, how can I do that? My codes below failed to do it.
[Code]....
The Header value of "ID1" is shown, but the cells only shows a '-' instead of 'New Column' sign.
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Mar 24, 2011
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Jan 11, 2011
I have a gridview, in an update panel, that's populated by an object data source when the page loads. This same Grid View is going to use a different data source and slightly different columns collection at runtime. The columns collection will be very similar, with one column added and three removed. Is this the best way to do this?
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