Forms Data Controls :: Changing Style In The Gridview Row Depending On The Row Value
Mar 1, 2011
I would like to change color of the gridView depending on the value from table that is bounded to the grid. I actually don't show this value on the grid. I tried by using additional field with visible=false, but the cell is string empty in this way. I don't know how to solve this in some other way?
I used this code, but as I said the value is empty:
[Code]....
Is it possible to solve this by getting value directly from bounded table and not from rows cell?
For reasons, I have an <a> tag in my master sheet rather than an ASP link. I want to access this html control from the server when a post back happens and change its style sheet. I have tried many a thing but as yet am still unsuccessful.
I have a field "Active" which can contain either 1 or 0. In the aspx form, I am displaying it in a checkbox in gridview. If the database value is 1, I should have the checkbox as checked, otherwise it should be unchecked. How can this be done.
I have a gridview and would like to display one of 5 icons depending on the value returned from the database for that row (simply just A, B, C, D or E). Which event in my datagrid should I be looking at to check what value I'm getting? I presume once I can check a value I can simply set an image source using if statements?
I have a gridview that is populating from a SQL DB and working fine. However, based upon certain data I find in fields in the SQL table, I want to place a 'n' or a 'y' in extra columns in the gridview that I am assuming need to be templatefields. My thought was I could maybe add 8 template columns and then I could put a 'y' in the appropriate column based upon the data I find the table. For the life of me, I cannot figure out how to do this. I want to do this at rowdatabound time ( i think) but I just cannot find out how to, in my code, put that 'y' in the columns. Is this the right way to do this or do I need to do it another way? How do I get that 'y' in the proper column?
I want if the header of a particular column contains a word "S", the header and row turns red. I used following code to make header red and it works fine. How to make it such that the rows also turn red if condition is met ? I cannot hardcode in columns since the Gridview is autogenerate colums as data structure keeps changing.
Protected Sub GridView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs)Dim HeaderRow As GridViewRow = GridView1.HeaderRowFor Each c As TableCell In HeaderRow.CellsIf c.Text.EndsWith("S") Then c.BackColor = Drawing.Color.OrangeRed End If Next End Sub
I was wondering if anyone could help me. I have a template field which has four itemtemplates that each hold a label in a gridview. These labels are always constant with the same strings. What I want to do is change the css formatting of these four labels depending on the value of a column. So the css formatting would have to be done for each row, not the whole column. I bind the gridview to a dataaccesslayer so there is no sqldatasource on the page. Does anyone have any idea how to do this and where it would be done. I will have the dataview with the data sorted in the correct order. The actual column that is used to alter the CSS will not be in the gridview although I could assign it to the datakeyname if that makes it easier as the data is not sensitive.
I'm trying to style my GridView's pager in such a fashion that when someone clicks on a button in that page, the page's button in the pager will turn yellow, or something.
how can I access the pager's buttons, and style each of them as I wish?
I have a column, description, in a GridView which has the most text data. As that column is defined as varchar(256), it can allow a string with 256 characters in it. In displaying, I don't want that column to stretch all the way. I use ItemStyle-Width to contain it to be 40% width. I also use word-break and word-wrap as:
I guess this attribute apply to the whole GridView1. I have a column called category with possible data as "LINKAGE", "CURTAIN", etc. Now "LINKAGE" is broken up into "LINKAG" and "E" with the "E" goes to next line. The word "CURTAIN" have the "IN" goes to the next line.
Now how can I apply the word-break and word-wrap to only the description column?
I have a grid view that is bound from my code behind. If the text of a label is equal to the value of a querystring, I want to apply a specific class/style that is in my .css. I've tried this, but doesn't seem to have any affect... How can I set the class for a column in the gridview if the two values match?
I need to change the background color of each menu item of asp menu control while the menu items are populate dynamically using a database. i.e. 1st menu item in black background, 2nd in green and 3rd in red and so on. If you can explain using C# it is great.
I've just created a Menu navigation that's linked to a SiteMapDataSource (which is in turn getting data from a .sitemap file that I've created). It looks great and acts accordingly, but my only question regarding this is there any way to just change the style (font color, in this instance) of just one element in the menu item? I just want it to stick out a little more than the rest of the menu items.
i'm trying to change the ImageButton on my site using resx files. i tried assigning my ImageButton with meta:ResourceKey="imgBtnSubmit". then in my resx file, i added imgBtnSubmit.ImageUrl and assigned it the url to my new ImageButton. this didn't work for me. could someone tell me if i'm doing something wrong or if there is some other way i could do this?
I have a validation method which passes the control of a failed validation ( IE TextBox in the Gridview row ) to a method which adds a validationError style.This all worked fine until I decided to use declarative css styling on the properties of the columns in the page IE Control-CssClass="someClass".
WHen I click the update and do find an error, I pass the control to have the validationError class appended. but it appears the declarative setting overrides this when it gets rendered.
