AJAX :: Find The Rating Inside A Gridview On Submit Button?

Jun 18, 2010

I have 5 questions to rate a product. These questions are in the database and I disply these questions to the customer in a GRIDVIEw. In order to make the rating easy, I give a tool like this- This tools is part of GridView in a TEMPLATE Field. A set of 5 stars will be available against each question. The user can rate each question by selecting the stars. Now, when the user clicks on the SUBMIT button, I want to receive the 'CURRENT RATING'. At present I am giving- Rating1.CurrentRating But, this doesn't give me any value because the rating tool is inside GRIDVIEW1. So, what changes should I make in Rating1.CurrentRating to receive the current rating value.

i am using this way
[Code]....

i am not able to get the selected rating value

on button submit i am using

AjaxControlToolkit.Rating rating1=(AjaxControlToolkit.Rating)row.FindControl("Rating1");

int rating =
Convert.ToInt32(rating1.CurrentRating);

It give value of first row but did not give me value of second row.

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