AJAX :: How To Use Rating Control Inside DataList
Jan 25, 2014How to use AJAX Rating Control inside ASP.Net DataList
View 1 RepliesHow to use AJAX Rating Control inside ASP.Net DataList
View 1 RepliesIn .aspx page:
<asp:DataList ID="dataList1" runat="server" RepeatLayout="Flow" RepeatDirection="Horizontal">
<ItemTemplate>
<div class="single-blog-post">
<h3><%# Eval("PName") %></h3>
<div class="post-meta">
[code]....
I want to set the ImageUrl property of IMAGE control in code.
I have a rating control that shows the average rating of a user supplied posting (think of a forum post that others will rate). So if the average rating for that posting is lets say 3 out of 5 all users will see 3 stars. If someone wants to rate the posting, then they could click lets say 4 stars and I save the rating to the database, re-average the current rating and display the result (which may or may not still be 3 at this point). So far so good. The problem comes in when a user wants to agree that it's 3 stars. Since the rating control currently shows 3 stars, choosing 3 again does not cause a postback. In my case even though the value didnt technically change, I need to capture the users choice so I can average it in and save that users rating. I also modify the UI so that I can show each user of the site what he/she choose as a rating.How can i get the control to let me know that a user choose a star rating even if its the same one the control is currently displaying?
View 3 RepliesHow to use ajax rating control with datalist control ....
View 1 Replies<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<div style="width: 100%; padding-top: 1em">
<img src="Abme/img/rating.png" alt="view" height="25px" width="25px" style="float: left" />
[Code] ....
My ajax rating panel
protected void OnRatingChanged(object sender, RatingEventArgs e) {
SqlConnection con = new SqlConnection(connStr);
SqlCommand cmd = new SqlCommand("Insert into rating(rating,postid) values(@rate,@pi)", con);
cmd.Parameters.AddWithValue("@rate", e.Value);
cmd.Parameters.AddWithValue("@pi", Request.QueryString["ID"]);
[Code] ....
The rating value get inserted to database async but updated rating is not displayed after update. I have to refresh page in order to display updated ratings.
I have this working except for one thing. After the user has voted I want to replace the submit with "Thank you" text.
In the aspx page I have a label that is not visible, with the text = "NotVoted". This label is not in the listview. In the listview I have a label that is not visible and a button that is. The rating control is called vidRating. In the vidRating_Changed event I have
lblVoteStatus.Text = "Voted"
ListView1.DataBind()
In the ListView1_ItemDataBound event I have
Dim lblVoted As Label = CType(e.Item.FindControl("lblVoted"), Label)
Dim btnSubmit As Button = CType(e.Item.FindControl("btnSubmit"), Button)
If lblVoteStatus.Text = "Voted" Then
btnSubmit.Text = "Thank you"
btnSubmit.Visible = False
lblVoted.Visible = True
End If
When I run this in debug mode, if the user has voted, ListView1.DataBind() is run, lblVoteStatus.text = "Voted", and the code in the IF statement is run. I get no errors, but the page doesn't change. I still see the button and I don't see the label text. If I comment out the if /end if statements, the page opens displaying the label text, not the submit button. So the controls are being found ok. What am I doing wrong? How can I disable or remove the submit button after the user votes?
I am now doing a project mobile musical website. I have used Ajax Toolkit in my last project and so that I know how to install it and work with it...
I have used CalenderExtender, TextboxWatermark, Password Strength, etc. But I am not familiar with the rating control. How does it work ?
Article [URL] .....
Above article show rating only integer part .
How can i show decimal rating on ajax rating control not any labels?
I am using AJAX Rating Control.I want half star rating.For Example,If My AVG Rating Count is 3 Then My Stars Wants to be show 3If My AVG Rating Count is 2.5 Then My Stars Wants to be Show 2 1/2 mark i.e., two & half stars.But,it was not showing then also it is showing 3 stars.
View 1 RepliesOnce clicking to rate, using the ajax rating control inside updatepanel, there is a problem and some variables loose the values....
So, What I did is to use the ViewState, but still the values are gone after click on the stars in order to rate...
what can be the problem?
[Code]....
I have 5 questions to rate a product. These questions are in the database and I disply these questions to the customer in a GRIDVIEw. In order to make the rating easy, I give a tool like this- This tools is part of GridView in a TEMPLATE Field. A set of 5 stars will be available against each question. The user can rate each question by selecting the stars. Now, when the user clicks on the SUBMIT button, I want to receive the 'CURRENT RATING'. At present I am giving- Rating1.CurrentRating But, this doesn't give me any value because the rating tool is inside GRIDVIEW1. So, what changes should I make in Rating1.CurrentRating to receive the current rating value.
i am using this way
[Code]....
i am not able to get the selected rating value
on button submit i am using
AjaxControlToolkit.Rating rating1=(AjaxControlToolkit.Rating)row.FindControl("Rating1");
int rating =
Convert.ToInt32(rating1.CurrentRating);
It give value of first row but did not give me value of second row.
I am trying to convert 22 rating control currentrating values to a double instead of int
I am also displaying in a label control so it is converted to String here is what I have
[Code]....
My display label displays
Rating is x stars out of 5.0 stars
I also record the results in a decimal 1.1 form
I did Convert.ToDouble(rate1.CurrentRating) + Convert.ToDouble(rate2.CurrentRating) .....
but I get a 7 digit after 0 return, how do i round that to a single point?
I have a custom control that renders different controls based on a property value. This all works correctly until i try and add a rating control to the control. When i render both controls in the CreateChildControls the control is rendered properly.
However when i try to add layout by overriding the RenderContents method and rendering controls there, an error is generated
Extender controls may not be registered after PreRender.The code shows both methods of creating the controls.
[Code]....
Can you tell the difference between Rating and RatingExtender asp.net ajax Control ?
View 4 RepliesI am using a Rating Control in my .ASPX page, but in the Page_Load in my code-behind, for some reason, can't access this control to set some properties of the control. Why is this happening and how can I access it in my code behind? Below is where the rating is set, but when I try to access ratingSystem. , nothing is coming up for me in Intellisense, and if I just type it anyway and compile / build, it gives me errors.
<asp:Content ID="Content2" ContentPlaceHolderID="PageBody" Runat="Server">
<asp:UpdatePanel ID="UpdatePanel2" UpdateMode="Always" runat="server">
<ContentTemplate>
<table border="0" cellpadding="0" cellspacing="0" width="100%">
<tr>
[Code]....
i am trying to bind rating control from my database. example like. Orkut Answer streangth. i have three option Yes, No and cant say and according database value, i want to show stranth for that option.
View 2 RepliesIs there a half-star rating control I can use for asp.net/ajax
View 1 RepliesI am using a Ajax Rating Control in Web User Control(".ascx").
The Images used for this control is not displaying in the browser, even though the control is getting loaded.
When i use the same code in the Aspx page it is working fine. It is only problem in Web User Control.
I have this:
[Code]....
This code throws an error:CurrentRating must be greater than MaxRatingParameter name: CurrentRatingWhen I change the code to this, it DOES work:
[Code]....
I have placed a ratngs control like the one shown in the tutorial. When I debug the page, I cannot see the ratings control. However I can hover over where the control is, and it will show the ratings tooltip (e.g. 1, 2, 3, 4 and 5), but no stars.
View 2 Repliesrating control in AJAX. I want that a person when he visits my site,he is able to rate the content only once after login. I have developed the rating part but the person can rate multiple times.
View 3 Replieswhen i using timer on update panel it current.rating values = null
Why ?
How to create 5 Star rating using jQuery and SqlServer.
View 1 Repliesi need a star rating system so that user can rate anything and that rating should be stored in database table.
View 1 RepliesI am usingĀ [URL] ....
And my question is the user should not vote again if he/she already voted....