I have placed a ratngs control like the one shown in the tutorial. When I debug the page, I cannot see the ratings control. However I can hover over where the control is, and it will show the ratings tooltip (e.g. 1, 2, 3, 4 and 5), but no stars.
View 2 Replies
I have a custom control that renders different controls based on a property value. This all works correctly until i try and add a rating control to the control. When i render both controls in the CreateChildControls the control is rendered properly.
However when i try to add layout by overriding the RenderContents method and rendering controls there, an error is generated
Extender controls may not be registered after PreRender.The code shows both methods of creating the controls.
[Code]....
I have a rating control that shows the average rating of a user supplied posting (think of a forum post that others will rate). So if the average rating for that posting is lets say 3 out of 5 all users will see 3 stars. If someone wants to rate the posting, then they could click lets say 4 stars and I save the rating to the database, re-average the current rating and display the result (which may or may not still be 3 at this point). So far so good. The problem comes in when a user wants to agree that it's 3 stars. Since the rating control currently shows 3 stars, choosing 3 again does not cause a postback. In my case even though the value didnt technically change, I need to capture the users choice so I can average it in and save that users rating. I also modify the UI so that I can show each user of the site what he/she choose as a rating.How can i get the control to let me know that a user choose a star rating even if its the same one the control is currently displaying?
View 3 RepliesI am now doing a project mobile musical website. I have used Ajax Toolkit in my last project and so that I know how to install it and work with it...
I have used CalenderExtender, TextboxWatermark, Password Strength, etc. But I am not familiar with the rating control. How does it work ?
Article [URL] .....
Above article show rating only integer part .
How can i show decimal rating on ajax rating control not any labels?
I am using AJAX Rating Control.I want half star rating.For Example,If My AVG Rating Count is 3 Then My Stars Wants to be show 3If My AVG Rating Count is 2.5 Then My Stars Wants to be Show 2 1/2 mark i.e., two & half stars.But,it was not showing then also it is showing 3 stars.
View 1 RepliesI am trying to convert 22 rating control currentrating values to a double instead of int
I am also displaying in a label control so it is converted to String here is what I have
[Code]....
My display label displays
Rating is x stars out of 5.0 stars
I also record the results in a decimal 1.1 form
I did Convert.ToDouble(rate1.CurrentRating) + Convert.ToDouble(rate2.CurrentRating) .....
but I get a 7 digit after 0 return, how do i round that to a single point?
Can you tell the difference between Rating and RatingExtender asp.net ajax Control ?
View 4 RepliesI am using a Rating Control in my .ASPX page, but in the Page_Load in my code-behind, for some reason, can't access this control to set some properties of the control. Why is this happening and how can I access it in my code behind? Below is where the rating is set, but when I try to access ratingSystem. , nothing is coming up for me in Intellisense, and if I just type it anyway and compile / build, it gives me errors.
<asp:Content ID="Content2" ContentPlaceHolderID="PageBody" Runat="Server">
<asp:UpdatePanel ID="UpdatePanel2" UpdateMode="Always" runat="server">
<ContentTemplate>
<table border="0" cellpadding="0" cellspacing="0" width="100%">
<tr>
[Code]....
i am trying to bind rating control from my database. example like. Orkut Answer streangth. i have three option Yes, No and cant say and according database value, i want to show stranth for that option.
View 2 RepliesIs there a half-star rating control I can use for asp.net/ajax
View 1 RepliesI am using a Ajax Rating Control in Web User Control(".ascx").
The Images used for this control is not displaying in the browser, even though the control is getting loaded.
When i use the same code in the Aspx page it is working fine. It is only problem in Web User Control.
I have this:
[Code]....
This code throws an error:CurrentRating must be greater than MaxRatingParameter name: CurrentRatingWhen I change the code to this, it DOES work:
[Code]....
How to use AJAX Rating Control inside ASP.Net DataList
View 1 Repliesrating control in AJAX. I want that a person when he visits my site,he is able to rate the content only once after login. I have developed the rating part but the person can rate multiple times.
View 3 RepliesHow to use ajax rating control with datalist control ....
View 1 Replieswhen i using timer on update panel it current.rating values = null
Why ?
How to create 5 Star rating using jQuery and SqlServer.
View 1 Replies<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<div style="width: 100%; padding-top: 1em">
<img src="Abme/img/rating.png" alt="view" height="25px" width="25px" style="float: left" />
[Code] ....
My ajax rating panel
protected void OnRatingChanged(object sender, RatingEventArgs e) {
SqlConnection con = new SqlConnection(connStr);
SqlCommand cmd = new SqlCommand("Insert into rating(rating,postid) values(@rate,@pi)", con);
cmd.Parameters.AddWithValue("@rate", e.Value);
cmd.Parameters.AddWithValue("@pi", Request.QueryString["ID"]);
[Code] ....
The rating value get inserted to database async but updated rating is not displayed after update. I have to refresh page in order to display updated ratings.
i need a star rating system so that user can rate anything and that rating should be stored in database table.
View 1 RepliesI am using [URL] ....
And my question is the user should not vote again if he/she already voted....
I have this working except for one thing. After the user has voted I want to replace the submit with "Thank you" text.
In the aspx page I have a label that is not visible, with the text = "NotVoted". This label is not in the listview. In the listview I have a label that is not visible and a button that is. The rating control is called vidRating. In the vidRating_Changed event I have
lblVoteStatus.Text = "Voted"
ListView1.DataBind()
In the ListView1_ItemDataBound event I have
Dim lblVoted As Label = CType(e.Item.FindControl("lblVoted"), Label)
Dim btnSubmit As Button = CType(e.Item.FindControl("btnSubmit"), Button)
If lblVoteStatus.Text = "Voted" Then
btnSubmit.Text = "Thank you"
btnSubmit.Visible = False
lblVoted.Visible = True
End If
When I run this in debug mode, if the user has voted, ListView1.DataBind() is run, lblVoteStatus.text = "Voted", and the code in the IF statement is run. I get no errors, but the page doesn't change. I still see the button and I don't see the label text. If I comment out the if /end if statements, the page opens displaying the label text, not the submit button. So the controls are being found ok. What am I doing wrong? How can I disable or remove the submit button after the user votes?
how to call AJax rating control in Form view ?
I have 1 rating control in fromview in code behid page i wan to call Ajax rating contrl in formview for determine event and property .
Two separate questions, but sufficiently intertwined that I'm going to try the two together....
Firstly - User Controls and Behaviours
I have a User Control which contains a few visual controls. I am attaching some behaviours by using GetScriptDescriptors and am passing some JavaScript to the browser using GetScriptReferences. That is all rock solid and working well. However, when developing, I did discover that I couldn't attach the ehaviours to the User Control itself - not surprising as rendering a User Control does not create a DOM element which represents the actual control. So, I have attached my behaviours to a "random" TextBox within the User Control.
So - first question, is there a better way to do that? For example, should I always be rendering a SPAN as an element to surround the control? Not sure what that would do to the robustness of the rendering. What is the right way to attach a behaviour to a User Control.
Secondly - Accessing those same Behaviours later
Assume I have placed a User Control on the page. That User Control exposes a Property (actually a Javascript Function of course) which does "something" to the control - for the sake of example we'll say that the function is set_Border(colour). I then have a behaviour on the same page (actually an Extender on a different control) which needs to call the function. I have a reference to the User Control in my script, so I have tried TheControlReference.set_Border('red') and find that my control doesn't support the set_Border method.
I guess this is probably because the behaviours are not attached to the User Control itself, but to a GUI element within it. Hence, I suspect that the answer to the second question lies within the answer to the first.
my problem as follow:
1-i have UpdatePanel contain Gridview
2- i have Ajax Control ToolKit HTML Editor OutSide My UpdatePanel and its not inside any control.
my problem when make HTMLedior (visible=false ) onpage event, MyupdatePanel Render Control Much Fast, but when i Make it visible its slow my application althougth this htmleditor not included in any update panel and its not refreshed.
