kindly any one tell me how i navigate on different Tab using image button. i am using TAB control(ajax Control) on my web page i have a tab container and in 4 tabs on it and i am trying navigate using image button(next,previous,first,last).
my page is just like this page of asp.net
I'm trying to navigate between tabs using an Image Button On each tab there is a button that navigates the user to te next tab. On the first tab, it works as expect from Tab 1 -> Tab2 But on the seconf tab, I get and error Java script
function MoveTab(tn) {
var container = $find('<%=
TabContainer1.ClientID %>').set_activeTabIndex(tn); ;
}
Button first tab that works ok
<asp:ImageButton
ID="ImageButton8"
runat="server"
OnClientClick="javascript:MoveTab('1')"
ImageUrl="~/Images/saveadd.gif"
/>
Button on second tab that gets error message
<asp:ImageButton
ID="ImageButton1"
runat="server"
OnClientClick="javascript:MoveTab('2')"
ImageUrl="~/Images/savereview.gif"
/>
Error Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidCastException: Specified cast is not valid. Source Error:
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Stack Trace:
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I am using ASP.Net AjaxControllTookit Tab Container and I have 9 tabs , on each tab panel i have some asp elements and a "prev" and "next" asp buttons. How to navigate next or prev on these asp buttons clicks.
I already try the c# code :
TabContainer1.ActiveTab = TabContainer1.Tabs[2];
Image Button in Datalist it ItemTemplate and Image Button Click Call Editor(Ajax)
View 1 RepliesI have a Master page and a user control on it.and i have a ASP Button on Usercontrol,the has to fire when ever i click on thats the default behaviour ..Now when the home page of my website loads and then i click on the button ,It works perfectly fine but when i navigate to other pages which have same master page the and then click on button the button does no trick!!
View 7 RepliesIn My Web Application i have one master page and Sign out button in menu. When i click log out button logout.aspx will load. i wrote the following code in that page form_load
session["id"]=null;
Response.Cache.SetCacheability(HttpCacheability.NoCache);
but after i click the log out button it will navigate to previous page.
I have a GridView that I load with a show button that drills into the details. I want to add a button that allows me to navigate back, but I'm not having much luck. I don't want to response.redirect("MyPage.aspx") because I don't want to have to reload the GridView.
I thought I code just add some java script to it:
Code:
ibtnBack.Attributes.Add("onclick", "javascript:history.go(-1);")
But that doesn't seem to work for some reason.
I need to add a button above a Calendar Control that "jumps" forward with 1 year in case the user wants to book for an event next year, without having to click the >>NEXT MONTH linkButton 12 times?
View 7 RepliesOn my Form I have 2 gridviews namely; gvCRSearch (that displays search results) and gvCRView (that displays all the change requests raised).. Now, when the records are more than 10 in gvCRSearch it automatically creates a navigation number i.e., 1 2 3 Same thing happens to gvCRView
What is wrong is that when I click the navigation i.e., ( for example 2) on gvCRSearch
1) the gvCrSearch becomes visible = false
2) the gvCRView if it has a navigation number is moved to 2
So the effect is seen the next view (gvCRView) and the gridview (gvCRSearch becomes invisible)
the asp is as shown;
Code:
<asp:GridView ID="gvCRSearchView" runat="server" ShowHeader="True" AutoGenerateColumns="False" DataSourceID="CRSearch"
BackColor="White" BorderColor="#600000" BorderStyle="Solid" BorderWidth="2px" CellPadding="3" Font-Size="89.5%"
ForeColor="Black" GridLines="Vertical" AllowPaging="True" PageSize = "10" AllowSorting ="true" CssClass = "MainGridView">
<Columns>
[code]....
Whats the best way to navigate from one popup to the next?- is it via :
ModalPopup1.Show()
and
ModalPopup1.hide()
or via the visible property?can you have several modal popups hiding and showing one after the other?- because I am trying to use 3, but not sure if its best to use .vb code behind page or if it can be done via the properties on the front end in visual web developer?
In a web page i have 5 tabs from 1 st tab to 2 tab i have to go by a linkbutton click not through header navigation so i created a link button and in the button click event
i have written the code like below
protected void lnkproceceed2tab3_Click(object sender, EventArgs e)
{
TabContainer1.ActiveTab = TabContainer1.Tabs[3];
}
its sitting in same tab i cant go to the next tab by a link button.
assume my page workflow is like below
if i click next button in 1 st tab it will load a pop up, then in that pop up i have two buttons one link button is to proceed to 2 nd tab another is go back to 1 st tab. where i got struck is from the pop if i click to proceed to 2nd tab i cant go to the 2nd tab.
our application, we use master page and inside master page we have aspx that loads certain controls in Update Panels via ajax calls. Depending on the left menu link clicked (which is also inside update panel), the content in another update panel would be loaded with appropriate user controls. Our issue is when the user cliecks on "Cancel" button in user control that is been loaded by Ajax call, we need to traverse back to the previous control or page.
View 1 Repliesi am tryin to show the image on the button click. the .cs file contains the database connections so when at the click of btn1 as the database searches i wanted it to display the image below. if i am goin wrong anywhere.and the file below is a .ascx file.
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<br />
<asp:Button ID="btn1" runat="server" OnClick="btn1_Click" Text="OK" style="width:155px; text-align:acenter;" colspan="1" Cssclass="buttonNormal" />
<asp:UpdateProgress ID="UpdateProgress1" runat="server"
AssociatedUpdatePanelID="UpdatePanel1"
DisplayAfter="100" DynamicLayout="true">
<ProgressTemplate>
<img border="0" src="~/Images/ajax-loader_2.gif" alt="" style="left:450px; top:250px"/>
</ProgressTemplate>
</asp:UpdateProgress>
</ContentTemplate>
<Triggers>
<asp:PostBackTrigger ControlID="btn1" />
</Triggers>
</asp:UpdatePanel>
it is supposed to show me that image when i click on btn1. the above code runs but with no results and also it places this line of code when the app is built
"<System.Web.UI.PostBackTrigger ControlID="btnAuswhal"></System.Web.UI.PostBackTrigger>"
is there a way to add a button to the editor that allows the user either to upload his image or submit a url for it,
View 2 RepliesI have a gridview with a link button, how can i call this in a modalpopoup extender.In bold i have the link buttons and below that is my modalpopup extender.aspx code Gridview:
[Code]....
ModalPopup:
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
I am using asp.net with vb for developing a website
I have a registration form in which i need to enter birthdate... m given an icon representing a calender and when the user click on that icon(image button) a calender should pop up and the selected date should be entered in the textbox in dat form..
I using a updatePanel which contains ImageButton and i have onmouseover for imgBtn . But onmouseover is not working
<asp:UpdatePanel ID="updateData" runat="server">
<ContentTemplate>
<input type="image" id="image1" name="imgBtn" runat="server" src="MyImg.gif" onmouseover="ChangeImg()" onserverclick="image1_click"/>
</ContentTemplate>
</asp:UpdatePanel>
******** javascript**********
<script type="text/javascript" language="javascript">
function ChangeImg()
{
document.getElementById('image1').src='AnotherImg.gif';
}
I am using scriptmanager in masterpage and my imagebutton click event is not being found in code behind and my javascript is not working and no events are firing.In fact,the imagebutton does not change the mouse icon to a hand when hovering...
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I'm using one Rating control and only logged in users can able to rate the article. Below is the code I'm trying
<ajaxToolkit:Rating ID="PostRating" runat="server" BehaviorID="RatingBehavior1" StarCssClass="ratingStar"
WaitingStarCssClass="savedRatingStar" FilledStarCssClass="filledRatingStar" EmptyStarCssClass="emptyRatingStar"
OnChanged="PostRating_Changed" Style="float: left;" CurrentRating="0" />
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This throws an error at Response.Redirect. Error message is "Response.Redirect cannot be called in a Page callback".
I'm also trying to implement a custom button on the toolbar, and have it working, sort of. I took the sample code and modified it so I only insert one button, to insert an image from a list in a database. I renamed the class from the original to CustomHTMLEditor and removed a few of the properties and methods I won't be needing. All this works 99%. The control is shown in the design and in my web page and the inserting of the image all works 100%, but there is an error in the designer : Unknown server tag 'customEditors:CustomHTMLEditor'.
Because of this, I cannot reference the control in code at all and thus not get the Content when the page is posted back.
Here are my two files in the App_Code folder:
From HTMLEditor.Samples.cs:
[Code]....
From HTMLEditor.CustomButtonsAndPopups.cs
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I am struggling on stop page refreshing when the image button is clicked.How i can i achieve this?I used triggers,javascript,.
View 6 Replieshow i can create insert image button for my html editor?
View 2 RepliesI am using ajax calender control in my project, its working fine.But when i click the image button to show the calender there i am facing the problen..after image click it is showing calender like this
jan feb mar
may jun jul
sep oct nov
so 4 8 12 months are not displaying whey are going outside of displaying range..
Can we upload images in asp, means I have a button and after clicking it dialog box should open and after selecting any 1 image from it i should be able to upload it
like we do in facebook and other social networking sites.
i wish to have a dialog prompt out by ajax when user click on an image button. Currently i able to include a simple text field and get the user input like this:
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