im developing website for my college.I have Recent updates in my home page in that i want to display newly added or updated things in recent updates.
sourcecode and Instructions for how to create link and how to redirect that to corresponding forms and how to create forms for particular updates dynamically then i want to make scroll the updates in GridView using Vb.net.
me how to add hyperlink in a gridview control
View 6 Repliesi have agridview in asp.netwich is connected to datatablei edit the culomn added the abelite to delet rowsbut when i press the delete choice i got an errorthe error wich i c istnx
The GridView 'GridView1' fired event RowEditing which wasn't handled. escription:An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.Exception Details: System.Web.HttpException: The GridView 'GridView1' fired event RowEditing which wasn't handled.Source Error:
[Code]....
I've got a gridview with a few textboxes in each row which I want to insert into a database, after a user clicks a submit button (thats outside of the gridview)
This is my code for the gridview
[Code]....
And this is my code for the button
[Code]....
But when I click the button it gives me this error
"Multiple controls with the same ID 'Label12' were found. FindControl requires that controls have unique IDs."
How do I give the controls unique IDs if they are in a gridview and the rows are database driven?
I am having one gridview in my asp form with one of the template field as imagebutton.
1. when i click on imagebutton the corresponding user profile opens in same tab....there is no option for open in new tab on right clickk..
open the user profilee in new tab.
I have two pages, the first one displays a list of products in a gridview, one column in the gridview is a hyperlink, this can be clicked on to get further details about the product. Each row in the gridview can be selected, certain details are added to an array (including the hyperlink column). I them want to display these details on page number two. All details are displayed except the hyperlink field.Has anybody any ideas as to what I'm doing wrong? The code is as follows:
[Code]....
and the second page:
[Code]....
If the user clicks on Inbox or Sent links, the inbox or sent tables with appropriate content taken from Message_Inbox database table should be shown on right. use asp.net panel controls hide/show to show/hide these tables. when user clicks on message subject link in these tables, the read-only view message page should be shown.
If the user clicks on Drafts link, the drafts tables with appropriate content taken from Message_Inbox database table should be shown on right.when user clicks on message subject link in these tables, the pre-composed form should be shown. the user should allowed to send or save this message.
I have the following code for the first part
protected void LnkButton_Click(object sender, EventArgs e)
{
LinkButton link = (LinkButton)sender;[code].....
How do I configure a column in the gridview to display a users name as the text and email address in a the mailto: link from the code behind page using C# so when the user clicks on the name it will open the default email client with the email address instead of the name?
View 4 Repliesi'm new to asp.net environment. i want to ask, i put column hyperlink at gridview. i click link and it will direct to another page that have textbox in it. how i want to pass info from gridview and display it at texboxt at next page?
View 5 RepliesI believe my SQL statement is sound. UPDATE [062610] SET abc = @abc FROM [062610] WHERE (dayID = @dayID) I cant seem to get my stupid variable @abc to sync with my GridView update command. I understand that I can let the GridView take care of my editting for me without having to write any code. But, I am running multiple tables and will be eventually needing to do this manually. Or at least as far as I know.
View 3 Replies<asp:TemplateField ShowHeader="false" ItemStyle-Width="50px">
<ItemTemplate>
<asp:HyperLink runat="server" NavigateUrl='<% string.Format("~/Tiff.aspx?Id={0}, Eval("ID")) %>' Target="_blank" Text="View" />
</ItemTemplate>
</asp:TemplateField>
When I m trying to click on it...It is not working or not firing any event,
May I know the reasong or any code behing is require
I have a Gridview of a database which displays the PDF files which I have uploaded onto the website.
I want to add a link/button to each record so that when I click it it opens the PDF file in Adobe Acrobat.
here's my url: http://nathan/mail/incomingmail.aspx?dc=8250&bg=-617370170
gridview code:
<asp:GridView ID="GridView1" runat="server" AllowPaging="True" AutoGenerateColumns="False"
BackColor="White" BorderColor="#DEDFDE" BorderStyle="None" BorderWidth="1px"
CellPadding="4" DataSourceID="SqlDataSource1" [code]...
How can one disable a Link Button in gridview. In gridview, I had defined linkbutton as :
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="lnkbtndownload" runat="server" CssClass="Links" CommandName="DownloadPdf" CommandArgument='<%#Eval("Client_ID")%>'>Download</asp:LinkButton></td>
</ItemTemplate>
</asp:TemplateField>
I Want to be able to replace this bitfield:
<asp:TemplateField HeaderText="Banned" SortExpression="bitBanned">
<ItemTemplate>
<asp:Label ID="Label5" runat="server" Text='<%# ShortDisplay("bitBanned") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>
with a link in my gridview that toggles the bit with a method from my dblayer
The ShortDisplay() method seen above looks like this:
protected string ShortDisplay(string strPerm)
{
string result = string.Empty;
if (Eval(strPerm) != null && (string.Compare(Eval(strPerm).ToString(), "True", 0) == 0))
result = "Yes";
else
result = "No";
return result;
}
As you can see it returns just a "yes" or "no", would like it to be a link when the bit is "Yes"
Is there a way based on the current user that when the page loads that the Delete option on the gridview is disabled?
View 1 RepliesI have a link button for one of the columns of the gridview, What I need to do to save the value that the link button has in the gridview on a text box and how can I open a new page on that link button
View 2 RepliesI have a gridview with edit, update and delete functioanlity.
I do also have a checkbox boolean field.
If checkbox1 is checked then I want to hide or disabled the delete button.
checkbox is in item template and Delete is not in item template, if i have to make the field of delete templeted then I will.
I am trying to create a basic gridview which has the basic edit and delete capabilities on a webpage using the MVC framework.I have bound the gridview to a LINQ Data source and I can retrieve all my records with no problem. However, when I click on the EDIT link, nothing happens at all. I have assigned my DataKey and viewing all the videos and tutorials on creating a gridview, this was how it is to get a gridview working.Steps taking:1) Created LINQ datacontext2) Created Controller 3) Created Index view4) Drag-and-dropped Gridview control onto Index view and link it to LINQ.5) Enabled CRUD functions on LINQ Datasource and Enabled Editing on Gridview.Can someone please tell me what is wrong or missing? I have tried different ways of getting this to work for 3 days now and I am at my wits end.
View 2 RepliesI am using VWD 2005 Express and Visual Basic.When my SQLDataSource feed my GridView, it does get the AutoNumber (GUID) of each record as well, to use it as a name for stored pictures. Pictures are not in the database but in a folder. Since I have several pictures, I do manipulate this ID with code and I add to it, pic1, pic2, etc and that is the final name for each picture, for each particular record. Example: The ID for one record in the database may be, 45623sdgd. If I have four pictures for this particular database record, the names will be, 45623sdgdPic1, 45623sdgdPic2, 45623sdgdPic3, and so on after Pic is added. After this I save these pictures in a folder.
Now, when I display the record information with a GridView, I get the AutoNumber of each record using: DataKeyNames="AutoNumber". I want to display a thumbnail picture link as well. But I really do not have many options in term of what control to use for the thumbnail inside the GridView. I tried the following controls unsuscesfully. HyperLinkField, can not add a picture to this one. ImageField, can not add a link to this one. ButtonField does not have a DataImageUrlField="AutoNumber" to get the AutoNumber. So since to be that my only opton is the asp:TemplateField. But it is giving me error with the coding. This is my coding,
Code:
<asp:GridView
ID="PublicClassifiedsSamplesGridView"
runat="server"[code].....
I have a search option which a person can use a multi select listbox. I have it coded so it would loop through to see if its selected or not. I also have a stored procedure where the sql statement is coded for the select statement. For some reason, its not populating my gridview. Where am I doing wrong? Below is the code and stored procedure.
[Code]....
[Code]....
i have 2 dropdownlist and gridview. Im trying to make a link after displaying the relational data in the gridview like below But how can i get the value and combine with the link
[Code]....
this is the all of my code
[Code]....
i have a table with a bindary data field in it (excel, pdf, word files etc).
In gridview i want to have a colum that the user can click on to open or download that file. The file is stored in the database and not on the directory.
I have searched some things but only came up with complex stuff.. I am trying to stay away from complex because i am a total noob.
so i have a gridview wherein there is a linkbutton ... when i click the linkbutton it will insert data to database...
View 2 Repliesim just trying to use this answer, but im getting an error on my page:
"A field or property with the name 'returnantID' was not found on the selected data source."
Im not really sure what the "returnantID" is but it appears my page isn't liking it, not sure if i was sopposed to cswap it out for some other data or not.
This is my current gridview:
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" GridLines="None"
DataSourceID="ObjectDataSource1">
<Columns>
<asp:BoundField DataField="ProductName" HeaderText="ProductName"
SortExpression="ProductName" />
<asp:BoundField DataField="Price" DataFormatString="{0:c2}" HeaderText="Price"
SortExpression="Price" />
<asp:BoundField DataField="Length" HeaderText="Length"
SortExpression="Length" />
<asp:BoundField DataField="Engine" HeaderText="Engine"
SortExpression="Engine" />
<asp:BoundField DataField="Colour" HeaderText="Colour"
SortExpression="Colour" />
<asp:BoundField DataField="Description" HeaderText="Description"
SortExpression="Description" />
</Columns>
</asp:GridView>
would just like the ProductName to link to the corresponding products page(using its Id)
p.s this is what i tried:
<asp:HyperLinkField DataNavigateUrlFields="returnantID" DataNavigateUrlFormatString="Details.aspx?id={0}" DataTextField="ProductName" NavigateUrl="Details.aspx" />
**Update** I changed the "returnantID" to "ProductName" which turned the name of my product into a link but clicking that link gave me this new error:
Input string was not in a correct format.