Forms Data Controls :: Tumbnail Link Picture In GridView?
Jul 15, 2010
I am using VWD 2005 Express and Visual Basic.When my SQLDataSource feed my GridView, it does get the AutoNumber (GUID) of each record as well, to use it as a name for stored pictures. Pictures are not in the database but in a folder. Since I have several pictures, I do manipulate this ID with code and I add to it, pic1, pic2, etc and that is the final name for each picture, for each particular record. Example: The ID for one record in the database may be, 45623sdgd. If I have four pictures for this particular database record, the names will be, 45623sdgdPic1, 45623sdgdPic2, 45623sdgdPic3, and so on after Pic is added. After this I save these pictures in a folder.
Now, when I display the record information with a GridView, I get the AutoNumber of each record using: DataKeyNames="AutoNumber". I want to display a thumbnail picture link as well. But I really do not have many options in term of what control to use for the thumbnail inside the GridView. I tried the following controls unsuscesfully. HyperLinkField, can not add a picture to this one. ImageField, can not add a link to this one. ButtonField does not have a DataImageUrlField="AutoNumber" to get the AutoNumber. So since to be that my only opton is the asp:TemplateField. But it is giving me error with the coding. This is my coding,
i have a gridview with a upload control in edit template. and a image control in item template bound to page that gets the new uploaded picture.the trouble is it does not return a picture no matter what i try??
I had a problem before with GridView displaying picture and it was solve as post [URL] shows. I am trying to apply the same coding to another GridView with a different configuration and I am having a hard time making the adaptation. May someone take a look at it. What I am trying to add to this GridView is code as:
I do a gridview code that when displaying the information that come from the database is not showing any error at all, but is not displaying the right picture. The problem, I think, is that the (Eval("....") is not reading the values that are coming from the DataKeysNames. Due to this the right pictures are not displayed. But in another column, just for testing purposes I was able to display the values from DataKeysNames with the Eval. So I do not know what is going on and to make worse browser is not giving me any error. So, this is the line that is not processing, reading or executing well:
now, i would like to add a little picture icon on the leftmost side of the gridview, that would allow a user to click on it...which will indirectly bring up a pop-up screen. In the pop-screen, i would like to add a textbox and a button to it, in which the user will be able to use to make an update to a field ID in the gridview.
I do have the following code for for a GridViewd that display pictures that are stored in a file. I am using AutoNumber(GUID) from the database to name the pictures before I stored them to the file. I can save up to 4 pictures using the same AutoNumber but adding these ending to it, Pic1, Pic2, Pic3 ,,,,etc.
The problem that I am having is that after I get the AutoNumber from the database, I want to display a standard picture on the GridView field if there is not particular picture associiated to this record in file. The name of the standard picture is located in the same file under the name of NoPicture.gif. How can I do this? So far this is my GridView code and it is working fine:
I have year wise Photo now i want insert the photo by year and month and date wise after i want the main page shown the year when i click the year it will be shown the month and i will click the month it will open by date after the photos will be shown .
im developing website for my college.I have Recent updates in my home page in that i want to display newly added or updated things in recent updates.
sourcecode and Instructions for how to create link and how to redirect that to corresponding forms and how to create forms for particular updates dynamically then i want to make scroll the updates in GridView using Vb.net.
I have two pages, the first one displays a list of products in a gridview, one column in the gridview is a hyperlink, this can be clicked on to get further details about the product. Each row in the gridview can be selected, certain details are added to an array (including the hyperlink column). I them want to display these details on page number two. All details are displayed except the hyperlink field.Has anybody any ideas as to what I'm doing wrong? The code is as follows:
If the user clicks on Inbox or Sent links, the inbox or sent tables with appropriate content taken from Message_Inbox database table should be shown on right. use asp.net panel controls hide/show to show/hide these tables. when user clicks on message subject link in these tables, the read-only view message page should be shown.
If the user clicks on Drafts link, the drafts tables with appropriate content taken from Message_Inbox database table should be shown on right.when user clicks on message subject link in these tables, the pre-composed form should be shown. the user should allowed to send or save this message.
How do I configure a column in the gridview to display a users name as the text and email address in a the mailto: link from the code behind page using C# so when the user clicks on the name it will open the default email client with the email address instead of the name?
i'm new to asp.net environment. i want to ask, i put column hyperlink at gridview. i click link and it will direct to another page that have textbox in it. how i want to pass info from gridview and display it at texboxt at next page?
I believe my SQL statement is sound. UPDATE [062610] SET abc = @abc FROM [062610] WHERE (dayID = @dayID) I cant seem to get my stupid variable @abc to sync with my GridView update command. I understand that I can let the GridView take care of my editting for me without having to write any code. But, I am running multiple tables and will be eventually needing to do this manually. Or at least as far as I know.
I have a link button for one of the columns of the gridview, What I need to do to save the value that the link button has in the gridview on a text box and how can I open a new page on that link button
I am trying to create a basic gridview which has the basic edit and delete capabilities on a webpage using the MVC framework.I have bound the gridview to a LINQ Data source and I can retrieve all my records with no problem. However, when I click on the EDIT link, nothing happens at all. I have assigned my DataKey and viewing all the videos and tutorials on creating a gridview, this was how it is to get a gridview working.Steps taking:1) Created LINQ datacontext2) Created Controller 3) Created Index view4) Drag-and-dropped Gridview control onto Index view and link it to LINQ.5) Enabled CRUD functions on LINQ Datasource and Enabled Editing on Gridview.Can someone please tell me what is wrong or missing? I have tried different ways of getting this to work for 3 days now and I am at my wits end.
I have a search option which a person can use a multi select listbox. I have it coded so it would loop through to see if its selected or not. I also have a stored procedure where the sql statement is coded for the select statement. For some reason, its not populating my gridview. Where am I doing wrong? Below is the code and stored procedure. [Code]....
i have 2 dropdownlist and gridview. Im trying to make a link after displaying the relational data in the gridview like below But how can i get the value and combine with the link
