I am working on List View to show Images dynamically. But my image folder is out side my Application folder(means on other drive or in same drive but not included in project ). Now if folder is inside project I know how to give Path , but outside Project it gives me problem in showing images.How to do that.in aspx
<asp:Image ID="ImgPic" runat="server" AlternateText='<%# Eval("CRGIMG_CARGO_IMAGE_PATH") %>'
I am working on a web application in which i was showing images with .jpg format initially. Now requirement changed and i have to show images with .tif format. I tried this but it is not showing images on my data list view.
View 1 RepliesI'm trying to display a list of images in the View. I have a list of URLs (List<string>) that I'm passing from the Controller using ViewData["imageURLs"], but nowI have no idea how to generate and display them?
View 2 RepliesI am working on one photogallery project, I have admin panel which will let administrators to upload images, save in the file system and name in database. I will retrieve all images in list view and let administrator handle all images which are verticle or horizontal.. I will let administrator to rotate image 90 degree or 360degree in listview edit mode. I have no idea about that.
View 2 RepliesI want to display images that a user uploads in a list view so that all the images a user uploads will appear as at the moment no images appear using the list view but the xml data source file gets updated. I am using VS 2008 usinf asp.net, vb and xml codes. What would I need to do so that the images appaer in the list view.
The code I have used in the aspx page is:
<asp:ListView ID="ListView3" runat="server" DataSourceID="XmlDataSource1">
<LayoutTemplate>
<div id="itemContainer">
<span id="itemPlaceholder" runat="server" visible="true" />
[Code]....
i am getting problem displaying images in list view. the pages shows only album name not any images.this is my code
<ItemTemplate>
I have a gridview, in an update panel, that's populated by an object data source when the page loads. This same Grid View is going to use a different data source and slightly different columns collection at runtime. The columns collection will be very similar, with one column added and three removed. Is this the best way to do this?
The other solution would be to create another grid view and data source to use when needed. The two Grid Views can be toggled off and on to use the correct one as needed. I've done this and it worked well, as far as I can tell. I'm curious if there are performance implications because of the additional Grid views and data sources. Or, if there are other reasons not to do this.
Which of these two ways is the best way to do this? Should I toggle between the two Grid Views at runtime or modify the grid view(datasource and columns) at runtime in the code behind?
I want to list all images in a horizintal way form the database where the id = number.ASP.NET, C#, SQL Server.
View 2 RepliesHow to generate columns in a list view dynamically?
View 3 RepliesI want to show grid view on only some selected radio button list item , how can i do this i am using this but it is not working..
<asp:RadioButtonList ID="RadioButtonList1" runat="server" RepeatColumns="4" RepeatDirection="vertical" OnSelectedIndexChanged="RadioButtonList1_SelectedIndexChanged" OnTextChanged="RadioButtonList1_TextChanged">
<asp:ListItem Text="Convention Center"></asp:ListItem>
<asp:ListItem Text="Conference Hall"></asp:ListItem>
<asp:ListItem Text="Auditorium"></asp:ListItem>
<asp:ListItem Text="Hotel/Resort"></asp:ListItem>
<asp:ListItem Text="Party Lawn"></asp:ListItem>
<asp:ListItem Text="Spa Resort"></asp:ListItem>
</asp:RadioButtonList>
------------------------------------------------------
protected void RadioButtonList1_TextChanged(object sender, EventArgs e)
{
If (RadioButtonList1.SelectedItem.Text == "Convention Center" || RadioButtonList1.SelectedItem.Text == "Conference Hall" || RadioButtonList1.SelectedItem.Text == "Auditorium" || RadioButtonList1.SelectedItem.Text == "Party Lawn")
{
GridView1.Visible = true;
}
else
{
GridView1.Visible = false;
}
}
I have grid view which databind from object datasource. my problem is i want to disply dynamic dropdown list on edit template based on the id which has in grid view. but still i can't figure out a way to do this.
View 1 RepliesI want to show only 3 Products in a row in a list view. here is my code.
[Code]....
I have gridview and want to show datalist in grid view view column on click of linkbutton show.
[Code]....
I have an Employee model that has a Name and Company
I want to be able to build multiple Employees in one CREATE view. I figured I need to create an IList<Employee> and do something like:
<%= Html.TextBoxFor(m => m[0].Name) %>
<%= Html.TextBoxFor(m => m[0].Company) %>
<%= Html.TextBoxFor(m => m[1].Name) %>
<%= Html.TextBoxFor(m => m[1].Company) %>
If a user clicks on "Add another employee", I want the view to make another form for the new employee:
<%= Html.TextBoxFor(m => m[3].Name) %>
<%= Html.TextBoxFor(m => m[3].Company) %>
And continue to add form items (and increment the array index if they click on it again).
Keep in mind that I need to build the form and the list dynamically in the create view. I don't already have a populated list of Employees.
i have the following scenario, i have a column of a gridview that shows me a text telling me is the user is allowed or not to access to some page, but now i just showing allow and deny, but i wanna show images that represent me the action, how can i do that?
View 3 RepliesI'm using Model-View-Presenter framework. When Loading a page, I'm having trouble setting the selected item that came from the Database.
In view, I know I need:
protected void ddlStatus_SelectedIndexChanged(object sender, EventArgs e)
{
presenter.DdlStatusSelectedIndexChanged();
// what should this pass?
}
Then in Presenter:
public void DdlStatusSelectedIndexChanged()
{
view.DdlStatus = ???
// Should I pass the SelectedIndex?
}
I also think that part of my problem is that DdlStatus I have as a List.
Interface:
List<StatusDTO> DdlStatus { set; get; }
The best I found is here (but needs formatted!) ---> [URL]
i want to know about how to show data in list view?
View 2 RepliesI want to show on one of my pages a slideshow type page. Basically I want it to show a selection of images from a folder and have the images scroll from right to left.
View 8 RepliesI'm creating an quiz application which queries the database and extracts the questions and choices. I use dynamically created controls such as a checkbox list and fill the values dynamically. How do I do this? Right now I have these functions:
array_random_init(); this creates a 10 element integer array from 1-20 - extract_question(i): this extracts a question indexed at i in DB, I created the controls and set the appropriate text in this function. - validate_question(i); this is called by button_click and validates the question i according to DB.
I understand I have to recreate the controls in Page_init on postback, but what should it look like? Do I need to add "if IsPostBack" in page_init, or do I create the controls in page_init() and reset their properties in page_load when I use extract_question(i)? Also, I cannot seem to clear the selected boxes on postback, I added page directive "enableviewstate=false" but it doesn't work.
I have drop down list box that I would like to show two columns, is this possible? Or can it be done with a list box?The query correctly retrieves all of the table data to be displayed, one colum is an abbreviation, the other a bit longer description.
View 2 Repliesi have created a simple view, and display it into gridview.. i have successfully created view but it is not shown in grid view , it return nothing...
protected void Button3_Click(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(@"Data Source=.SQLEXPRESS;AttachDbFilename=E:
arenHDI-AJAX-TK-Calendar-CSApp_DataDatabase.mdf;Integrated Security=True;User Instance=True");
con.Open();
SqlCommand cmd = new SqlCommand("select * from nview", con);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataSet ds = new DataSet();
da.Fill(ds);
GridView1.DataSource = ds;
GridView1.DataBind();
con.Close();
}
I'm having troubles remembering how to grab the list view's state, or page, so that when you leave the list, you can return to the list view page you left on. I have a data pager, and I have hyplerlinks for items in the list view that take you to a file upload or file delete page, and then returns to the list view. It returns to the list view's initial state (first page).
View 1 RepliesIn the below code it does not show the images in the ouput though the img is in the specified location is there any other way to specify the location?
<%@ Control Language="C#" AutoEventWireup="true" CodeBehind="CreditCardList.ascx.cs" Inherits="ResortManagement.Component.CreditCardList" %>
<%@ Register TagPrefix="exact" Namespace="Exact.Hospitality.Core.Web" Assembly="Exact.Hospitality.Core"%>
<%-- Credit Card --%>
<table>
<tbody>
<asp:Repeater ID="rptCreditCards" runat="server" OnItemDataBound="rptCreditCards_ItemDataBound" OnItemCommand="rptCreditCards_ItemCommand" >
<ItemTemplate>
[Code....]
I am trying to load every image *.png in a folder on my site. I simply want every image to be shown. One after the other, all on one page. Displaying a single image seems simple enough, but going through the entire directory is tough. How could I do this with minimum code using asp.net with vb as the language?
View 2 Replieshow can i display the images from folders dynamically,i mean when i add it ,this code generated
<img id="1" src=//retreive from folder>
some one told me to write server.MapPath in the src
it is worked for the first image only,i want to display all the iamges from the folder
in the html tag <img.....>