Forms Data Controls :: Generate Columns In A List View Dynamically?
Jan 21, 2011How to generate columns in a list view dynamically?
View 3 RepliesHow to generate columns in a list view dynamically?
View 3 RepliesI am developing an application using ASP.NET with C#.NET.in my application i have a gridview control and radobutton list having the values as Manufacturer and Distributor. based on the radiobutton selected value,the gridview will bindedup.
i am using SQL SERVER 2005 as backend server. in my database i have one table with columns as
1.mfropendate
2.mfrclosedate
3.mfrawarddate
4.distopendate
5.distclosedate
6.distawarddate
My gridview has 3 columns as Opendate,closedate,awarddate.
if user select the radiobutton as manufacturer,only mfropendate,mfrclosedate,mfrawarddate have to bind. and if user select the distributor the remaining 3 fields will have to bind. for that i had write a storedproc as create procedure sp_GetDraftBids as begin select mfropendate as opendate,mfrclosedate as closedate,mfrawarddate as awarddate, distopendate as opendate,distclosedate closedate,distawarddate awarddate from draftbids end GO
i.e i had taken the alias names for that fields so that i will bind the only 3 columns to grid view as opendate,closedate,awarddate.
My gridview code is
[Code]....
here i had taken the same alias names as i have to bind only 3 columns to gridview.when i run my application i am getting the records in data table with column names as opendate,closedate,awarddate,opendate1,closedate1,awarddate1.i.e it does not allow the same alias name.
for two radio button conditions i.e for manufacturer and distributor the gridview binded with opendate,closedate and awarddate columns as i had binded the gridview boundfields withat names.
but when user select the distributor radiobutton i have to bind the opendate1,closedate1 and awarddate1 to the gridview. for that should i can i change the storedproc are any other solution is there?
Need row editing on page_load for all the cells and need to validate each cell entry. Means cell1 one entery isvalid it fills thrid cell and insert or update to a table in the database. How do i handle on tab clicking to update in databse.
View 1 RepliesI am trying to generate a Grid view from database, in one of my database columns the values are 'y' and 'N'. and i need to show this values in a check box .I tried to keep a check box in item template and tried to bind it, but could get much success.
[Code]....
I have grid view which databind from object datasource. my problem is i want to disply dynamic dropdown list on edit template based on the id which has in grid view. but still i can't figure out a way to do this.
View 1 RepliesI have drop down list box that I would like to show two columns, is this possible? Or can it be done with a list box?The query correctly retrieves all of the table data to be displayed, one colum is an abbreviation, the other a bit longer description.
View 2 Repliesim showing 3 rows and 2 columns in a Gridview...I want to generate a 3rd column at runtime in a Gridview ....
only 1 LinkButton in Gridview at position row1 and column 3
only 2 LinkButton in Gridview at position row2 and column 3
only 3 LinkButton in Gridview at position row3 and column 3
Index outof range?GridView2.Columns[6] as BoundField I use Auto-generate field .
How to manipulate GridView2.Columns as BoundField with auto-generate field?
[code]....
I coded in code behind to dynamically generate a gridview as the columns of the gridview changes based on user selection. In the gridview I have dynamically generated controls like textbox, dropdown list etc.I have a few filtering options about, for example: listbox which will postback on change and causes the gridview content to change as well.My problem is: since the controls are randomly generated and every postback will read dataset from database and reload, the naming of the controls are dynamically generated too.
View 10 Repliesmy listview having 3 columns:SI.No,HallticketNo,Name.
I bind data to listview but the "SI.No" column in listview showing Empty data.
So,how to generate serial number in listview ?
How to Dynamicly generate HTML from server side ?
I'll give you some examples..
Now im using Response.Write("<a> hi hi </a>"); something like this and i generating stuff dynamicly depends on what is on the SQL..
I was wondering how facebook does it or all those sites is generating a full page depending on the SQL...
[Code]....
My output is all work in C# code behind
I am returning an IList to my model of data about users. I want my end users to be able to select which columns they want to see.
I know I can do this with a huge "if statement" however, I know there must be a better way. I have created an Enum with the column names. I feel if I could take the IListItem.EnumName I would be set. However, I'm not too sure on how to do this.
I have gridview which auto generate column is false, and I add some template columns, databind with a class ClassA . it works fine. now, I need add some columns to this gridview. the problem is: I do not know the # of columns that will be added (it is dynamic), and the data with these columns is in ClassA, but it is a array (or list). so, there is no public property for these data, only the array.
now, what I did is: I dynamically add template column to the gridview (column header ...), so, it shows the correct columns in the gridview, but how can I bind the data? I found some example, i.e.
[URL]
but it is for aleady know the data field (which is a public property in the class). all I have is just a array, and I need bind them to the newly created columns in sequence.
<?xml version="1.0" encoding="utf-8" ?>
<mappings root="sound" child="item" delimiter=",">
<mapping pos="0" name="product" type="Element" />
<mapping pos="1" name="partID" type="Attribute" />
<mapping pos="2" name="numberInStock" type="Element" />
<mapping pos="3" name="numberOnOrder" type="Element" />
<mapping pos="4" name="deliveryDate" type="Element" />
<mapping pos="5" name="supplierStreet" type="Element" />
<mapping pos="6" name="supplierCompany" type="Element" />
<mapping pos="7" name="supplierPhone" type="Element" />
<mapping pos="8" name="orderedBy" type="Element" />
</mappings>
this is my xml file
what i need is a table with 9 columns say item,product....orderedBy
the design requirement is like,when we click on a item in grid view a pop up window has to be generated where a particular user can enter details and save them and then again minimise the window..the changes entered in the window has to be saved in db..is there any possiilty to do this kind in grid view control ??
View 3 RepliesI am working on List View to show Images dynamically. But my image folder is out side my Application folder(means on other drive or in same drive but not included in project ). Now if folder is inside project I know how to give Path , but outside Project it gives me problem in showing images.How to do that.in aspx
<asp:Image ID="ImgPic" runat="server" AlternateText='<%# Eval("CRGIMG_CARGO_IMAGE_PATH") %>'
I hve this gridview
v style="overflow: auto; height: 250px">
<asp:UpdatePanel UpdateMode="Conditional" ID="up1" runat="server">
<ContentTemplate>
<asp:GridView ID="gv" runat="server" DataKeyNames="row_id" AllowSorting="True" AutoGenerateColumns="false">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:CheckBox ID="chkDelivery" runat="server" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Sequence No">
<ItemTemplate>
<%# Container.DataItemIndex + 1 %>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
</ContentTemplate>
</asp:UpdatePanel>
i want to add this two columns dynamically to gridvew in codebehind.
I want to create columns in gridview dynamically based on rows in a table and each gridview colum should have a checkbox. When I Click the save button, I want to save the checkbox state. How Can I do this ?
View 2 Repliesis there a way I can add a column dynamically from code behind to the gridview in my page?
View 5 Repliestried to use gridview.columns.count to see if there are any columns bt it shows zero, second how shall i et the names of columns in the gried view at runtime i need them to be stored in an string array
View 2 RepliesI have a requirement where on the left hand side we have a tree view control and on the right hand we have dynamic columns.
Below screenshot gives an idea of the requirement. what is the best way to implement this?
Year1, Year2, Year3 are dynamic and are based on the user input.
I am having datagridview control with dynamically added BoundField columns.I want to have tetxboxes in each cell of the gridview so taht user will enter data in gridview textboxes and at last on button click it will be saved in database.
View 14 RepliesI have been searching for some time on the net for guidance on this question. Finally thought I will ask here...
I have a gridview that needs to be generated from code behind. There is a column with a name field and the remaining columns give the different user-ids linked to that id. Like this:
-- NAME, ID1, ID2, ID3......
The Name column will be populated from a table that has the Name as well as number of ID's associated with that name. eg [Name1][3]
I need to display linkbuttons that link to user-id related documents in columns 2 to n for each name.How do I dynamically add linkbutton columns from code behind?
How to resize the width of columns of grid view? I want a column 250px wide.How I can do this?
View 4 Replies