Web Forms :: How To Display A Random Number In Textbox
Mar 21, 2011I've web page with 1 textbox.
If I open that page I want to display a random number between 0-9 in that text box, how?
I've web page with 1 textbox.
If I open that page I want to display a random number between 0-9 in that text box, how?
generating random numbers in texbox and then submit to database. code should check if the generated number already exist in database before submiting to database.
View 1 RepliesI have a form and I want each form to have a unique number when it is filled out so it will go into the database. How can I set this up so when the page loads in the label it will say 1 then the second time it loads it will say 2?
View 1 Replieshow to start/formulate codes on this.I want that in every form load, textbox1 will generate autonumber and random number for textbox 2.
View 2 RepliesI need to display multiple textboxes upon value entered in one textbox ...
ex: if i enter 3 in textbox1 then down to it , it must display 3 textboxes ...
is it possible to make an online form generate a random reference number unique to that form?
I'm using C# and .net 3.5
Random rand = new Random((int)DateTime.Now.Ticks);
int numIterations = 0;
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 100);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(50, 100);
Response.Write(numIterations.ToString());
[Code]....
This is what i have so far. first 2 number gives 1-50, then 1-100, then last two give 50-100
now i need to make the first 2 numbers give even or odd numbers. how can i do this?
i will set a random number for uploading files. how could i do that?
is it possible to set a random name with 20-50 characters?
Not sure if I'm approaching this correctly but this is what I've got and what I'm trying to do
I have a table with 10 Labels in it (Labels Id A1 thru A10)
I'm trying to have each label assigned a random number using 0-9
Need to have each labels number value different from the other
Code Below:
Randomize()
A1.Text = Int(Rnd() * 10)
A2.Text = Int(Rnd() * 10)
A3.Text = Int(Rnd() * 10)
A4.Text = Int(Rnd() * 10)
A5.Text = Int(Rnd() * 10)
A6.Text = Int(Rnd() * 10)
A7.Text = Int(Rnd() * 10)
A8.Text = Int(Rnd() * 10)
A9.Text = Int(Rnd() * 10)
A10.Text = Int(Rnd() * 10)
Recently, I am working on the website where I am generating random number and storing it in database as the primary key. So, this key would be foreign key for many table, now how would I generate the random number and check if random number does not have duplication? Is there any function to check if number is not duplicate?
View 1 RepliesI want to generate a unique random number everytime a user submits a form. As the form is submited the data of the form should be placed in a database and a unique random number should be generated so that the user can later use this unique random number to reterieve his details from the database that refer to his unique random id. The unique random number should be atleast 9 digits long.
View 3 RepliesI have a feedback form in my website. After submitting the feedback (using Submit button), form's Reference number should generate and showed to the user (with successful message) in a "Pop up" as below:
i.e, your feedback is submitted successfully. Your refrence number is 'xyz10'
This refrence number should be unique for every user who fills the feedback form.
how can i generate different number,it is generating the same number
Random rand = new Random(100000);
rand.Next();
I want to generate a 16 digit random account number that should be unique in database for every new user of my website. kindly guide me how can i generate a 16 digit unique number.obviouly i understand that i would have to check that number in my database table for uniqueness and if that generated number already exist then i would have to generate it again.
View 11 RepliesI would like to create a confirmation number using both letters and digits just like when you book your flights, the confirmation number looks like '9Z3RG6R'
View 7 RepliesI'm trying to implement a code that will generate a fix lenth alphanumeric code; number from 0...9 and capital letters A...Z. I want the code to be formated as this: XXX-XXX (where X representes a random character between 0...9 and A...Z). It doesn't matter if the letters and/or the numbers repete. But it will be great if the don't. I'm using VB.Net. How can I do this?
View 4 RepliesI need to generate a random number which starts fro 750000 and should increment one by one for generating other number.
ex: 750000
second it shoul dbe 750001
I want to generate simple random number in webpage ... like remain one button,when I clicked show a random number.
View 6 RepliesI need to generate random number in oracle.i need to get always 3 digit random number(100 to 999)
View 5 RepliesI have an ASP.NET application that relies on the Random class to generate a pseudo-random string. It uses the following code (this is part of a larger piece of sample code provided by Google for apps SSO):
public static class SamlUtility
{
private static Random random = new Random();
private static char[] charMapping = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p' };
public static string CreateId()
{
byte[] bytes = new byte[20]; // 160 bits
[Code]...
This normally works very well, but from time to time it starts generating a string of 'a'. From what I can tell from debugging, Random simply stops returning random numbers and instead fills bytes with the same value over and over. I've patched this by using a GUID instead, but I'm curious what happened in the original code. I'm assuming some form of entropy exhaustion, but I can't find any reference in the docs. Also, each time this has happened, performing iisreset restored the correct behavior.
I am using the asp.net and framework 2.0 with Ajax enable web.i have a text box and when user will enter "a" or number in this will search the name started from "a" character or number if he or she enter the number basically we can say live-search.
Employee search: Textbox.In this text box she/he will enter the first character of name or first number of employeeno and according to the a character name will search in list.
How can I generate a 7-digit random number and special character string in a textbox on a button click event, in VB.Net?
View 2 RepliesHow can I display images randomly when a page refresh occurs? Images are stored as (image type) in a ms sql database.
Is it possible with the Image control in visual studio?
Table: id(int), img(image)
I have a web user control with DataList control in it. In my .aspx page, I have a report header, an empty panel as a place holder, a report footer.In my .aspx.vb file, I'll loop through a list of departments. Within each department, I'll load a label to display the department name and the user control for the data, and add both the label and user control to the panel. So there are two variables:
the number of departments and the number of records in a user control.
Now I need to display the current page number and the total page number in the report footer. Is it doable? How? I'm thinking of this approach: declare a page variable count, count the number of department name labels and the number of records in a user control. When the total count reaches a number, such as 20, I'll break the page. This way, I can get the the page current number and the total number of pages. But how to add a page break to an asp.net page?
I have implemented a adrotator to display random images using ajax. I also need to display another image at left side corner on the adrotator image continously.
View 4 Replies