Web Forms :: How To Make Textbox1 Generate Autonumber And Random Number For Textbox 2
Jan 22, 2010how to start/formulate codes on this.I want that in every form load, textbox1 will generate autonumber and random number for textbox 2.
View 2 Replieshow to start/formulate codes on this.I want that in every form load, textbox1 will generate autonumber and random number for textbox 2.
View 2 Repliesgenerating random numbers in texbox and then submit to database. code should check if the generated number already exist in database before submiting to database.
View 1 Repliesis it possible to make an online form generate a random reference number unique to that form?
I'm using C# and .net 3.5
Recently, I am working on the website where I am generating random number and storing it in database as the primary key. So, this key would be foreign key for many table, now how would I generate the random number and check if random number does not have duplication? Is there any function to check if number is not duplicate?
View 1 RepliesI want to generate a unique random number everytime a user submits a form. As the form is submited the data of the form should be placed in a database and a unique random number should be generated so that the user can later use this unique random number to reterieve his details from the database that refer to his unique random id. The unique random number should be atleast 9 digits long.
View 3 RepliesI want to generate a 16 digit random account number that should be unique in database for every new user of my website. kindly guide me how can i generate a 16 digit unique number.obviouly i understand that i would have to check that number in my database table for uniqueness and if that generated number already exist then i would have to generate it again.
View 11 RepliesI would like to create a confirmation number using both letters and digits just like when you book your flights, the confirmation number looks like '9Z3RG6R'
View 7 RepliesI'm trying to implement a code that will generate a fix lenth alphanumeric code; number from 0...9 and capital letters A...Z. I want the code to be formated as this: XXX-XXX (where X representes a random character between 0...9 and A...Z). It doesn't matter if the letters and/or the numbers repete. But it will be great if the don't. I'm using VB.Net. How can I do this?
View 4 RepliesI have a feedback form in my website. After submitting the feedback (using Submit button), form's Reference number should generate and showed to the user (with successful message) in a "Pop up" as below:
i.e, your feedback is submitted successfully. Your refrence number is 'xyz10'
This refrence number should be unique for every user who fills the feedback form.
I need to generate a random number which starts fro 750000 and should increment one by one for generating other number.
ex: 750000
second it shoul dbe 750001
I want to generate simple random number in webpage ... like remain one button,when I clicked show a random number.
View 6 RepliesI need to generate random number in oracle.i need to get always 3 digit random number(100 to 999)
View 5 RepliesHow can I generate a 7-digit random number and special character string in a textbox on a button click event, in VB.Net?
View 2 RepliesI've web page with 1 textbox.
If I open that page I want to display a random number between 0-9 in that text box, how?
I've a web form whereby my invoice number is "CS00x" whereby x is the auto number supposedly to be generated using the following codes:
[Code]....
However, when the first time I login and try if the invoice number can be inserted into the database in access, it would display CS0001 which is the result I want. So, I went on to try out using another account to login.But it gives me error "The changes you requested to the table were not successful because they would create duplicate values in the index, primary key, or relationship. Change the data in the field
or fields that contain duplicate data, remove the index, or redefine the index to permit duplicate entries and try again."Also, I found out that it can only generate CS001 but not CS002 so on.
I'd like to generate an OId number in a specific textbox on a specific page which comes out of date and time, for example if today is may 27th 2010, 9:45 am,it will generate the number 270520100930
date: 27
month: 05
year:2010
time: 0930
i have gridview that shows some information i want to have column that be autonumber shows the row number of gridview.for example i have 7 row in gridview it show 1 for first row ,2 second row,3 third row,... how can i do that?
View 3 Repliesi try to make register users page with username and password i want to makr the textbox for username accept only english and number and special carachter lik "_ - @ . " how can i do it
View 2 RepliesI want to generate a unique random number everytime a user submits a form. As the form is submited the data of the form should be placed in a database and a unique random number should be generated so that the user can later use this unique random number to reterieve his details from the database that refer to his unique random id. The unique random number should be atleast 9 digits long.
View 5 Repliesi want to generate random URL for the users who want to download my file which is located in my server (http://servername/book/book.pdf) after he bought from us. and that URL should expire after few days lets say (1 week) .
View 2 Repliescancel plane ticket before 4 hours of departure time if dep time is 08:00:00 AM then Passengers can cancel ticket till 04:00:00 AM? I have two textboxes textbox1 and textbox2 in asp.net(vb) webform I want If in textbox1 the time would be appear as 08:20:20 AM Then in textbox2 the time would be automatically generated 4 hours before as compared to textbox1 i.e ( the time in textbox2 the time would be appear as 04:20:21 AM ) Means simply logic i want ... if the time in Textbox1 is 08:00:05 PM then autogenerated time in textbox2 will be 04:00:06 PM Means whatever the time in Textbox1 the textbox 2 will autogenerate time in 4 hours time slot.
View 1 RepliesI have a Gridview with 12 columns, Jan, Feb...Dec.
I have a textbox value that could be 1, 2,...12
I want if textbox value is 7, then column Aug-Dec in Gridview is editable when in update mode and the column in Jan-Jul is not updatable (eg make it label instead of textbox).
How can I do this ?
a control or some code I can use to generate a random testimonial from a selection of testimonials.
I want a random testimonial to appear each time a page is loaded.
This site does not currently use a database so a solution that uses a text file or spreadsheet is preferred.
Random rand = new Random((int)DateTime.Now.Ticks);
int numIterations = 0;
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 100);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(50, 100);
Response.Write(numIterations.ToString());
[Code]....
This is what i have so far. first 2 number gives 1-50, then 1-100, then last two give 50-100
now i need to make the first 2 numbers give even or odd numbers. how can i do this?
i will set a random number for uploading files. how could i do that?
is it possible to set a random name with 20-50 characters?