DataSource Controls :: Generate Sql Row To XML Mode?
Apr 26, 2010I have this query to generate sql row to XML Mode.
[Code]....
I want the result is like this:
[Code]....
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Jan 11, 2010I am currently working on this situation that I could not find any other resources online to help me
Everything is working fine through VS2008 debug mode, or run without debugging ( database connectivity and everything works)but however when i copy the whole project and set up the IIS,
everything work except for database connectivity. I could not seems to read from the database which currently I am using a attached .mdf file
the error shown is as below :
Server Error in '/' Application.
Object reference not set to an instance of an object.
Description:
An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.NullReferenceException: Object reference not set to an instance of an object.
Source Error:
[Code]....
Source File: Signup.aspx.vb Line: 23 Stack Trace:
[Code]....
but however when i run on VS 2008, I am able to read the data from the database successfully,
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[Code]....
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[Code]....
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book.xsd:
[Code]....
Book.cs:
[Code]....
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Jul 5, 2010I am generating a unique Ref number using this sql statement: SELECT REPLACE(STR(CAST(CAST(NEWID() AS binary(5)) AS bigint),12),0,0) as REF Subsequently, I need to insert this REF into sql database table in stored procedure. Here is what I did in my stored procedure:
USE [iBankRecords]
GO
/****** Object: StoredProcedure [dbo].[stp_addPayee] Script Date: 07/05/2010 21:57:07 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER PROC [dbo].[stp_addPayee]
(
@CUSTID char(10),
@PAYEEACCNUM nvarchar(20),
@PAYEEACCTYPE char(10) ,
@PAYEENAME char(20),
@PAYERINITIAL char(20),
)
AS
DECLARE
@ReturnValue int
INSERT INTO PAYEE (CUSTID, PAYEEACCNUM,PAYEEACCTYPE,PAYEENAME,PAYERINITIAL, REF)
VALUES (@CUSTID,@PAYEEACCNUM,@PAYEEACCTYPE,@PAYEENAME,@PAYERINITIAL, REF)
IF @@ERROR<>0
BEGIN
PRINT 'ERROR'
SET @ReturnValue=1
RETURN @RETURNVALUE
END
ELSE
BEGIN
SET @ReturnValue=0
RETURN @RETURNVALUE
END
May I know how do I have generating a unique ref num and inserting the REF into the above statement?
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And thats what i have done so far: [Code]....
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here is error log
[Code]....
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