I am trying to implement a way to send email templates in my application and would like to populate an ActionResult view with data and then output the view HTML as a string to use as the body of my email. I found the following
blog post but have not been able to get it to work correctly in my app and was wondering if anyone had been able to implement something similar. The issue that I am running into is that I have created one controller, EmailController, to handle all generation and returning of the the view strings. So for instance if I am in my home controller and I have a contact form whose action is Contact when the user submits the contact form I want to call the email controller to get the correct action result for the email template and upon successful send of the email redirect the user to a success action on the home controller.
've created a Search partial view and it works, except for my view model. What i mean is, the partial view sends a string to my ActionResult Method, but only a string, that is not related to the view model that the partial view is built in. If i tell my ActionResult method to receive the view model in which the partial view is built in, it always tells me that i have null values. Here's my code This is my partial view:
[Code]....
Now here is my Model in my MoviesSearch view model:
How can I use use an actionResult to return both a view and a partial view. Actually in case of an ajax request it should send a partial view else it should send a view.
public ActionResult Test(string Name ="", DateTime? Date= null, string sex="" ) { myModel model = new myModel(Name, Date, Sex); if(IsAjaxRequest) return PartialView("partialView", model) else return View(model); }
[HttpPost] public ActionResult Start(SomeViewModel someViewModel) { ... }
that based on some conditions returns things like return View("Invalid"), View("NotFound"), View("Run", anotherViewModel), etc. The problem is that no matter what view I present, the URL does not change to reflect the new controller/action. This poses a problem when my View wants to post to a different action. How can I fix this?
When i select a dropdownlist and submit , dropdown selected value comes to textbox and freetextbox. Its working well
Again i m adding contents to freetextbox
Again i select a dropdownlist and submit , dropdown selected value comes to textbox and freetextbox. The newly selected value only comes to textbox and freetextbox, but my old contents are not exists in freetextbox.
I need old contents and dropdown selected value comes to freetextbox.
I have just started using MVC. I created the MVC application and was playing around with it.When you call the http://localhost/home/Index/ on the sample MVC application the Index method of the controller home gets invoked and the view Index.aspx is displayed and similarly when we call http://localhost/home/About/ then the About method of the Home controller is invoked and the About.aspx page is displayed
this is the first controler which is calling my applciation I am getting all my studentinfo for updating studnetcan i call this et in updateresult Action result?
public ActionResult getresult(StduentInfo et) { return PartialView("Student", et); public ActionResult updateresult(Stdentinfo et) [code]...
I am implementing a view for Food. (ASP.NET MVC2) Then depending on the type (say fruit or vegetable for example) I will change the view.
Can I do this without creating a seperate view for fruit and vegetable?
I.e. Say we have url structure like [URL] and don't want [URL] [URL]
So I want to be able to change the view depending on the type. I'm using a tabstrip control from telerik, to give you an of the difference in the views - it'd just be say - not displaying one particular tab for Veg, and displaying it if fruit, for example.
Can a view accept two different view models ? so when we hit [URL] the code determines what type the object is (Fruit or Vegetable) then sends either FruitViewModel or VegetableViewModel ? If I just send one viewmodel how can I control the logic to display or not display certain things in the view?
I have a grid view in which I have table.On Click of a particular td in the grid I open a modal window of ajax.I want to send the id of a particular row to the modal window.Here is the Code for aspx.
when i send data for show a list of the project to view i got this error
The model item passed into the dictionary is of type 'BentaAccounting.Models.Project', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[BentaAccounting.Models.Project]'.
I am doing loan sysytem where you first select the amount you want to borrow and click apply. the problem im getting is i cant seem to be able to redirect the amount selected to my second view where the client fill up the form.
I'm rewriting a messaging module and the old asp application has a send button image and it used HTML submit button. My new application is asp.net. Can I use the asp send button image to response.redirect to the View message page?
I have a dropdown with several items (hardcoded) and next to it I have a submit button - which invokes an Action in the controller. I can successfully identify the submit button in the controll using the name and value attributes of the submit button, but how can I send the selected value of the dropdown control to the controller?
[Code]....
Then inside the controller I can identify that the submitButton with value of "Start Task ..." has been clicked, but I do not know how to know which value in the dropdown was selected?
our implementation of an mvc site is being done in a very weird way but none the less it is still mvc.
I have an issue that on a certain page, when you click a button to download a document, it retrieves from a web service a byte array of a document. This is not an issue as i pass this byte array into the view data to allow me to access it in our controller.
This is the code in the controller.
[Code]....
Now this all works ok but as expected the result is rendered out into the current window. Is there anyway at all i can trigger a new window to render out the document?
I have the following action result class that looks for a content type of "application/json" in the request and executes a jsonresult or the default result. My problem is that I don't know how to test the ExecuteResult method.This is the method in question:
I have an action that returns a file path as ActionResult, I want that action to return a file path and change the View. Is there a way I can make an action return more than one ActionResult?
By default ASP.NET MVC uses ContentResult for controller method that return result not inherited from actionresult type. That is why if we will return some poco entity it will be only its type name.Could I overload something in controller to make it return jsonresult by default.Example:// return json product representation instead of product typename
public MyController: Controller { public Product MyAction() { return new Product { Name = "Foo", ID = 1 }; [code]...
