Pass ViewModel With JQuery Post?
Mar 23, 2011
I'm trying to do a post with jQuery in an MVC application, according to this SO answer here:Can jQuery do a POST of a ViewModel to a Controller in ASP.NET MVC?The difference is I am using it to delete an item in a dynamic view (never mind the fact that I'm posting a delete directly, this is a closed site by authorization, and I will use jQuery to confirm, I just don't want the user to have to go to a new page). And I therefore need to be able to send both the id and the ViewModel (the ViewModel to save any added items before deleting any). I'm not particularly happy with the solution by and large, but at this point I just need to get it to work!So I tried to figure out how to send both the id and the ViewModel according to the SO post above, but I can't figure out how to get the ViewModel in with the named parameters. This doesn't work:
$(".delete").click(function () {
$.ajax({
type: "POST",
[code]...
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Nov 23, 2010
What I have is a table that holds 3 input elements, They represent order, name, value. The user can add a new row of 3 inputs to add as many of these sets of data as they want.
To accomplish the dynamically adding in of inputs I use jquery's clone method. That works fine and I am able to iterate through each and grab the values, however the real pain I am having is that when the user has entered in all of the data I want to pass that data to an asp.net page through jQuery's post method. How do I go about passing an array of strings so that I send this format to the asp.net page, and when I've done that how do i parse the data on the asp.net side of it.
Desired Data Format:
["Name|Link|Order", "Name|Link|Order", "Name|Link|Order"]
jquery Code so far:
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e.preventDefault();
$("#addPanel").slideUp(300);
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var saveString = "";
$("#addTable tbody>tr").each(function () {
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var n = $(this).find(".hsaname").val();
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[Code]....
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I have a view model as such:
public class MyViewModel
{
public MyObject myObject{ get; set; }
public List<MyList> myList{ get; set; }
}
I have a view with a form strongly typed to MyViewModel This view allows you to enter values for the properties of MyObject, as well as create a list of MyList objects. The List part works fine although I thought that would be the more difficult of the two. Assuming MyObject has a property Description I create a textbox to enter the value as such:
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EDIT: more info
The first line of the view is:
@model MyApp.ViewModels.MyViewModel
And the Action method:
[HttpPost]
public ActionResult Create(MyViewModel myViewModel)
{
}
I am passing a new MyViewModel into the partial view to begin...
public ActionResult Create()
{
MyViewModel model = new MyViewModel();
return PartialView(model);
}
EDIT 2
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[Code]....
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