I'd like to generate an OId number in a specific textbox on a specific page which comes out of date and time, for example if today is may 27th 2010, 9:45 am,it will generate the number 270520100930
date: 27
month: 05
year:2010
time: 0930
I've a Textbox
I can enter a Number which is greaterThan "0" or I can enter text which is only "NUMEROUS"
so
If I enter 0 (or) negetive Number (or) any text other than "NUMEROUS", i must display error msg Like
"Don't Enter 0/Negetive No./text other than "NUMEROUS"
generating random numbers in texbox and then submit to database. code should check if the generated number already exist in database before submiting to database.
View 1 Replieshow to start/formulate codes on this.I want that in every form load, textbox1 will generate autonumber and random number for textbox 2.
View 2 RepliesI am using the asp.net and framework 2.0 with Ajax enable web.i have a text box and when user will enter "a" or number in this will search the name started from "a" character or number if he or she enter the number basically we can say live-search.
Employee search: Textbox.In this text box she/he will enter the first character of name or first number of employeeno and according to the a character name will search in list.
I need to generate sequential number for my new Users. For every user i need to show sequential number for their ID. it should be dynamic one.once they they click register i need to show this sequential number in Label.
View 3 Repliesis it possible to make an online form generate a random reference number unique to that form?
I'm using C# and .net 3.5
public string ACtivationKey()
{
string allowedChars = "";
allowedChars = "a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,";
allowedChars += "A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z,";
allowedChars += "1,2,3,4,5,6,7,8,9,0";
[Code] ....
I am generating a new order reference id in a class Called GeneratePdf.cs
I use it as
GeneratePdf gp = new GeneratePdf();
string orderunique = "ORD-" + gp.ACtivationKey();
var uniqness = db.OrdersMasters.Where(x => x.OrderRefNumber == orderunique).Select(x => x.OrderRefNumber).Count();
I want to run a check if the reference number is not present in database. if its present generate new ...
Recently, I am working on the website where I am generating random number and storing it in database as the primary key. So, this key would be foreign key for many table, now how would I generate the random number and check if random number does not have duplication? Is there any function to check if number is not duplicate?
View 1 RepliesRandom rand = new Random((int)DateTime.Now.Ticks);
int numIterations = 0;
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 50);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(1, 100);
Response.Write(numIterations.ToString());
Response.Write(' ');
numIterations = rand.Next(50, 100);
Response.Write(numIterations.ToString());
[Code]....
This is what i have so far. first 2 number gives 1-50, then 1-100, then last two give 50-100
now i need to make the first 2 numbers give even or odd numbers. how can i do this?
I want to generate a unique random number everytime a user submits a form. As the form is submited the data of the form should be placed in a database and a unique random number should be generated so that the user can later use this unique random number to reterieve his details from the database that refer to his unique random id. The unique random number should be atleast 9 digits long.
View 3 Replieshow i can generate a gridview with a fixed number of rows that is entered from a textbox
my gridview has a column with dropdownlists the others contains textboxes?
I need to generate a Unique Reference number that has 7 digits.
It should be formatted in the following way:
1st: B (Ball), G (Gift), C (Cat)
2nd: represents year of booking A(2010), B(2011),C(2012), etc
3rd: represents the month of booking J(Jan),F(Feb),M(Mar),A(Apr),Y(May), U(Jun), L(Jul),G(Aug), S(Sep),O(Oct),N(Nov),D(Dec)
4th: days of booking A(1st) - Z(26th), 1(27th) - 5(31st)
5,6,7th: These are counters for the number issues each day. Each can be A-Z,0-9 giving a total of 46,656 combinations. So 0 is first, then 1, 2, 3, 4, 5, 6, 7, 8, 9, A-Z, then 00 to 0Z, then 10 to 1Z, then 20 to 2Z, etc
Now , the 1st Digit is a Character that I generate based on a condition and that shouldn't be a problem.
my listview having 3 columns:SI.No,HallticketNo,Name.
I bind data to listview but the "SI.No" column in listview showing Empty data.
So,how to generate serial number in listview ?
I have a feedback form in my website. After submitting the feedback (using Submit button), form's Reference number should generate and showed to the user (with successful message) in a "Pop up" as below:
i.e, your feedback is submitted successfully. Your refrence number is 'xyz10'
This refrence number should be unique for every user who fills the feedback form.
I have a system that generates a invoice in the form of a pdf document. I just want to know, what is the correct way to generate a reference number for the invoice. Preferebly I want something in the line of D100001, D100002 etc. The "D" stand for the kids school grade "D", "E","F" etc.
View 4 RepliesI was thinking of formatting it like this
TYYYYMMDDNNNNNNNNNNX
(1 character + 19 digits)
Where
T is type
YYYY is year
MM is month
DD is day
N is sequencial number
X is check digit
The problem is, how do I generate the sequencial number? since my primary key is not an auto increment integer value, if it was i would use that, but its not.
EDIT can I have the sequencial number resets itself after 1 day (24hours).
P201012080000000001X <-- first
transaction of 2010/12/08
P2010120810000000002X <--- second
transaction of 2010/12/08
P201012090000000001X <--- First
transaction of 2010/12/09
(X is the check digit)
I want to generate a 16 digit random account number that should be unique in database for every new user of my website. kindly guide me how can i generate a 16 digit unique number.obviouly i understand that i would have to check that number in my database table for uniqueness and if that generated number already exist then i would have to generate it again.
View 11 RepliesI would like to create a confirmation number using both letters and digits just like when you book your flights, the confirmation number looks like '9Z3RG6R'
View 7 RepliesI'm trying to implement a code that will generate a fix lenth alphanumeric code; number from 0...9 and capital letters A...Z. I want the code to be formated as this: XXX-XXX (where X representes a random character between 0...9 and A...Z). It doesn't matter if the letters and/or the numbers repete. But it will be great if the don't. I'm using VB.Net. How can I do this?
View 4 RepliesHow can I generate unique numbers in JQuery? I use the unique numbers for the Shopping Cart ID.
View 6 RepliesHow do I generate a unique number in c# without the database? (max 17 digits). EDIT: digits only.
View 2 Repliesi hav a gridview ... now i need to add certain number of rows... say 5 rows .... which would b blank .. the rows consist of itemtemplate of textboxes.. here is the grid ...
[Code]....
now i am binding this gridview with certain data say :
[Code]....
now the problem is if the row contains 2 data originally ... then it alwz shows up with only two rows with binded data... but what i want is 2 (databinded rows ) + 5 (empty rows with textbox ) = 7 grid view rows .... now how to do it ... after i hav binded the textbox with data already....with some empty columns corresponding to the above code ?
I need to generate a random number which starts fro 750000 and should increment one by one for generating other number.
ex: 750000
second it shoul dbe 750001
I want to generate simple random number in webpage ... like remain one button,when I clicked show a random number.
View 6 Replies