C# - How To Retrieve All GridViewRows From A GridView Control With Paging Enabled
Jan 2, 2011
I am working on Add To Cart Functionality, and I have added a GridView control with paging enabled. In the GridView, I show the quantity in a text box and handle the OnTextChanged event for that textbox. Now the problem, is how can I keep the changed quantity text in session or view state, and in which row, so that I can update my GridView and bind that data again to the GridView?
Here I took GridView with id gvMaster.
[Code]....
I want to show changed quantity value in grid with paging enabled.
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Feb 3, 2010
how to get the total row counts in a Gridview control with default paging enabled? My gridview control is bind to an ObjectDataSource control.
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foreach (GridViewRow row in this.MyGridView.Rows)
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Oct 21, 2010
time for some expertise. I have a datalist which contains a radiobutton in the itemtemplate. This radiobutton is disabled (set enabled to false) by default. On the html output I have a checkbox, which, when ticked, enables the radiobuttons through javascript. This is all working fine. The rb's are enabled and I can check them. However when the page is posted back. The checked property is always false.
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[Code]....
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Oct 9, 2013
I currently have a GridView control on my aspx page with paging enabled and I need to loop through the entire row collection/count to process the selected records. With my current code, it will only loop through the current page of GridView row.
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May 7, 2015
I tried to keep all the data in the gridview when paging, but when I try to save it, which appears in my database only when it is active pages .. ex: in the first and second page I have data in gridview .. when I save, the stored in the database only the first or second page of course .. so I like to keep all my data in gridview when paging..
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string sql1;
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{
[Code].....
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Jul 28, 2010
I have a gridview and having trouble with display when the webpage is saved as pdf. I can see just the first page of gridview. If I dont do pagination and save the file, the gridview just breaks up and half is displayed on firstpage and half on next page. is there a way that if the gidview cannot fit on one page, I can break it and display rest of it on nextpage?
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Dec 2, 2010
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Feb 12, 2010
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Jan 3, 2010
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Sep 21, 2010
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May 13, 2010
Is there any good solution for ajax enabled Grid with pageing and sorting which only brings the required data from database? I mean it should only bring the data from the database which is to be displayed on the particular page number of the grid.
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Jan 27, 2011
I have a gridview which has TWO rows (assume this will always be the case). The grid is set in a way that whenever "Edit" is clicked, whole gridview turns into edit mode. (I mean all the rows)
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Mar 31, 2010
I have a problem while displaying the data from the grid to the excel.I have implemented pageing and the problem is the page that is displayed is only exported to the excel not all the pages.
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Jan 10, 2011
I'm trying to extend the GridView control to enable sorting and paging for any situation.
When using my control I am fetching data from a database and filling a DataSet with it, then binding the GridView upon every page load. My first question would be, is this the correct approach?
To sort the GridView I am overriding the OnSorting method which stores the sort expression and direction in the ViewState, then creates a DataView and utalises the Sort method to sort the underlying data. It then sets the Data Source to this DataView and rebinds the GridView.
Paging is handled by OnPageIndexChanging which simply sets the PageIndex property and again rebinds the GridView.
My problem is; when any control causes a postback my GridView is no longer sorted, presumably because it is persistently rebound. If I don't rebind it then the GridView is empty on postback since the data isn't automatically stored in the ViewState. I have considered saving the data source in the ViewState but I would assume that this is bad practice for large amounts of data? - also DataViews are not seralisable.
The only solution I can think of currently is to override OnDataBound and sort the data every time. This results in a double sort when paging triggers a postback which seems inefficient. Code illustration of this below,
[Code]....
I'm looking for the cleanest 'best practice' solution as this is a learning exercise more than anything else.
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Mar 25, 2010
I am trying to do efficient paging with a gridview without using a datasource control. By efficient, I mean I only retrieve the records that I intend to show.I am trying to use the PagerTemplate to build my pager functionality.In short, the problem is that if I bind only the records that I intend to show on the current page, the gridview doesn't render its pager template, so I don't get the paging controls.It's almost as if I MUST bind more records than I intend to show on a given page, which is not something I want to do.
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Aug 6, 2010
currently it works if i remove the PagerSetting or remove the PagerTemplate so if have both (PagerSetting & PagerTemplate) then my page number not display.
my qeustion is: how can i display both (PagerTemplate and PagerSetting) togather at the bottom of the Gridview? plese see the below source code.
[Code]....
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Nov 4, 2010
reference to create Paging User control.
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Dec 17, 2010
I have an IEnumerable object (IEnumerable<Class>) and I would like to retrieve a specified line from the object. So if I'm on page two I would like to select row two from the IEnumerable object and then pass it on to another class etc. I'm a bit stuck at the moment, any ideas?
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Nov 18, 2010
Is there a way to use the GridView paging and having the links not use JavaScript. So that when you click on the page number 5 (for example) that link is a hyperlink.
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Dec 13, 2010
I have a gridview control on a .aspx page (content form).
Paging is enabled on gridview control. It displays the page numbers at the bottom of the .aspx page. When I click on a page number say 3, I get error saying the "Exception Details: System.Web.HttpException: The GridView 'GridViewReconresults' fired event PageIndexChanging which wasn't handled."
Do I need to write special code to handle the paging? Because there is a grid in another page and it has bound columns and I didn't write any code for paging and it works perfectly fine.
Here is the code in the .aspx page that I have problem.
[Code]...
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Feb 20, 2010
I am a new user of ASP.NET 2.0 (VB.NET)
I am facing a problem related to GridView Control
I have a table <UsersDetail> with following structure in MySQL
FIELDNAME | DATATYPE
---------------------------------------
userid | Numeric
Userlogin | Varchar(25)
Userpassword | Varchar(25)
Firstname | Varchar(50)
Lastname | Varchar(50)
---------------------------------------
I wrote a code to fetch data from this table :
Dim Con As New MySqlConnection
Dim Cmd As New MySqlCommand
Dim Adp As New MySqlDataAdapter
Dim DTable As DataTable
Con.ConnectionString = ConfigurationManager.ConnectionStrings("dbConString").ConnectionString
Cmd.CommandType = CommandType.StoredProcedure
Cmd.CommandText = "sp_FetchAllUsers"
Cmd.Connection = Con
Adp = New MySqlDataAdapter
Adp.SelectCommand = Cmd
DTable = New DataTable
Adp.Fill(DTable)
GridView1.DataSource = DTable
GridView1.DataBind()
Basically Gridview controls is used to display data in tabular format.
but due to requirement I changed its layout to columner in following manner
<asp:GridView ID="myGridView" runat="server" AutoGenerateColumns="false" AllowPaging="True" PageSize="3" Width="520px">
<Columns>
<asp:TemplateField HeaderText="User ID">
<ItemTemplate>
<asp:Label ID="Label3" Text='<%#Eval("userid") %>' runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="User Login">
<ItemTemplate>
<asp:Label ID="Label4" Text='<%#Eval("Userlogin") %>' runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Pack Amount">
<ItemTemplate>
<asp:Label ID="Password" Text='<%#Eval("Userpassword") %>' runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="For">
<ItemTemplate>
<asp:Label ID="First name" Text='<%#Eval("Firstname") %>' runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Validity">
<ItemTemplate>
<asp:Label ID="Last name" Text='<%#Eval("Lastname") %> Months' runat="server"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
Now come to the problem, i set the AllowPaging="True" and page size to 3 records/page but when click on paging links it displays the following error :
The GridView 'myGridView' fired event PageIndexChanging which wasn't handled.
Description:
An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.Web.HttpException: The GridView 'myGridView' fired event PageIndexChanging which wasn't handled.
Source Error:
[Code]....
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Apr 5, 2012
I want to preserve state of Checkbox in Gridview, I do not have Checkall Checkbox. How to use below code
[URL] ....
This code because I do not have CheckboxAll check box... How to preserve Checkbox status while paging ?
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Dec 24, 2010
here's a situation and I would appreciate your response.
I have programmatically created the Wizard control:
Page_Load(obj s, evargs e)
{
Wizard ClaimDetailWizard = new Wizard();
foreach(int item in selectedItems)
{
//create new step
//added custom control to new step
//add step to wizard
}
//added wizard to a placeholder on a page
}
Based on List I get from Session i added new steps to my wizard To each step I had added a custom control
Each custom control in tern contains another custom Gridview Control in it.
So here's the problem when the page loads for example for two steps. All is good Wizard does what it's supposed to do.
But when I try to use sorting or paging in that custom Gridview. Somehow it displays the gridview I should see in the next step of the wizard.
Also what I'm noticing through debugging. Is that when I press next in the wizard I go back to the original page where I do all of the code specified above, and it recreates the wizzard. But it goes to the next step. Is this the way wizard supposed to work? Just doesn't seem very efficient.
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Jun 21, 2010
I want to create user control for gridview paging, so it may be reusable for every grid in my application, my user control should be like below, how its possible
eg: previous 1,2,3,4,5,6,7,8,9,10 More If i clicks more link next 10 pages of records should be visible, how its process?
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