Data Controls :: Show GridView Selected Row Details Inside JQuery Dialog Modal Popup?
Dec 18, 2013How to show Gridview selected row in popup using Jquery asp.net 2010
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<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" Width="100%" PageSize="5" AllowPaging="True" OnPageIndexChanging="GridView1_PageIndexChanging" BorderColor="#e5e4e2" BorderStyle="solid" BorderWidth="2px">
<RowStyle CssClass="Grid" />
<Columns>
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[CODE]..
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[URL] ....
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Below is the code attached for your reference
<asp:Content ID="Content1" ContentPlaceHolderID="head" Runat="Server">
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.ui/1.8.9/jquery-ui.js" type="text/javascript"></script>
<link href="http://ajax.aspnetcdn.com/ajax/jquery.ui/1.8.9/themes/start/jquery-ui.css"
rel="stylesheet" type="text/css" />
[Code] ....
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Show JQuery Modal Dialog From Serverside?
Mar 2, 2011this is the first time i'm using jQuery dialogs so this question might be somewhat simple but i haven't found answers on this yet.
I'm using ASP.Net Ajax to perform an asynchronous postback when user enters something into a Textbox(actually scanning a barcode). This is working like a charm.Now i need to let the user decide between two options under certain conditions. Therefore i need the postback to decide if this dialog must be shown and what content it has.
Q: How to open a jQuery UI (modal) dialog from serverside, let the user choose an option, postback again to server and handle this decision.
I think i need AjaxControlToolkit.ToolkitScriptManager.RegisterClientScriptBlock to register the script that opens the dialog, am i right? If yes, what script opens the dialog onload?
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[Code]....
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<script type="text/javascript">
function WebForm_OnSubmit() {
if (typeof (ValidatorOnSubmit) == "function" && ValidatorOnSubmit() == false) {
$("#validation_dialog").dialog({
title: "Validation Error!",
modal: true,
resizable: false,
[Code] ....
The WebForm_OnSubmit() function is being rendered by the BaseValidator control and in the form tag te following attribute is being added: onsubmit="javascript:return WebForm_OnSubmit();
I am running into a problem on a page which has an UpdatePanel. The input field with the validator (1 to make it simple) is in a Panel within an UpdatePanel. The Panel is set to Visible=False at the first Page Load. There's a button inside the UpdatePanel which makes the Panel with the Validator Visible.
When this happens, the WebForm_OnSubmit() function and the onsubmit="javascript:return WebForm_OnSubmit(); attribute of the form tag are not being rendered because it's an AJAX callback and the form tag is outside the updatepanel (in a master page), so the validation summary will not be shown in the jquery dialog.
Validation is being performed, so the validation summary wil be shown in a div on a page, but the validation is not being called by the WebForm_OnSubmit() function in this case, because it's not being rendered.
Here's the markup of the page:
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:Button ID="btnNew" runat="server" Text="New" />
<asp:Panel ID="pnlEdit" runat="server">
<table>
[Code] ....
So, when the validators are not visible at the first load and they will be made visible by an AJAX callback, the WebForm_OnSubmit() function and the onsubmit="javascript:return WebForm_OnSubmit(); attribute of the form tag are not being rendered on the pag. Because of that, the WebForm_OnSubmit() function will not be called and the validation summary will not be shown in the JQuery dialog (although it is being shown in a div on the page). How can I get the Validation Summary to be shown in de JQuery dialog in this case?
Is there another function that has to be overriden for this case? I know I can use a Full Postback for the New button and then all the stuff needed is being rendered on the page, or I can make the panel not visible by using a style, but I don't prefer that because there are a lot of pages with this situation.
One solution is to use a dummy textbox with a dummy validator (with a dummy validationgroup) of which I set the display to none. Then this dummy validator will cause the the WebForm_OnSubmit() function and the onsubmit="javascript:return WebForm_OnSubmit(); attribute of the form tag to be rendered.
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Apr 25, 2014I have Gridview in UpdatePanal but their is problem with template field
<asp:TemplateField HeaderText="EDIT">
<ItemTemplate>
<asp:LinkButton ID="lnkEdit" runat="server" ToolTip="Edit Unit" OnClick="lnkEdit_Click"
CausesValidation="False"><img src="IMG/screw-driver.png" alt="" /></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
and link button click event is
protected void lnkEdit_Click(object sender, EventArgs e)
{
GridViewRow clickedRow = ((LinkButton)sender).NamingContainer as GridViewRow;
ScriptManager sm = (ScriptManager)Page.Master.FindControl("smanager");
sm.RegisterPostBackControl(clickedRow);
lblUnitID.Text = clickedRow.Cells[0].Text;
txtUnitName.Text = clickedRow.Cells[1].Text;
txtDecimal.Text = clickedRow.Cells[2].Text;
btnUnit.Text = "Update";
}
but text box value is not set but when we do it in PostBackTrigger is work.
can we do this AsyncPostBackTrigger.
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Sep 20, 2015I have tried your script when loaded more rows in Gridview, multiple panels are getting open onwards 2nd row button click of gridview.
<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="Panel3.aspx.cs" Inherits="pnlCallback.Panel3" %>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
[code]....
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