Forms Data Controls :: FileUpload Issue In DetailsView?
Sep 16, 2010I'm using FileUpload Control to update a table and it works fine but,the issue arise when not entering a file, then the record set the picture field value to NULL
View 2 RepliesI'm using FileUpload Control to update a table and it works fine but,the issue arise when not entering a file, then the record set the picture field value to NULL
View 2 RepliesI have a detailsview with an upload image to the database. Image is save as binary file in database, and imagename is the name of the file. I'm able to load the image to the database using FileUpload. How do I get the image name to the database? Is there any method like OnInserting or something that allows me to retrieve the file name and save to database?
<asp:TemplateField HeaderText="Image" SortExpression="Image">
<ItemTemplate>
<img src='../Handler.ashx?PromoID=<%# Eval("PromoID") %>' />
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I am trying to arrange the information from a SQL record into a 3 column by 3 row table to fit the form presentation that I want. I have placed on the page 3X3 table and then tried to place a detailsview in the first cell for the first picture called P1dv.
I have place a detailsview in the last cell that would control the paging of information called Controldv. I need to fiqure out how to link P1dv paging to Controldv page action. I am using visual web dev. 2005. I am not updating or editing these are read only views.
example of what i need the form output to look like:
picture1 picture2 picture3
name1 name2 name3
Contact1 contact2 contact3
what i ave coded as of now:
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I´m trying to link the gridview to detailsview and I used this page as my inspiration:
http://quickstarts.asp.net/QuickStartv20/aspnet/doc/ctrlref/data/detailsview.aspx
But I´m trying to do that programmatically, not with the sqldatasource. So I wrote the method that binds data to Detailsview and I call it in the page_load. The problem is that I have to click two times on the select button to view the detailsview. The first time I click on the select button nothing happens.
I have a gridview with a Select button. Clicking the Select button for a particular item, I need its full details displayed in DetailsView. how I can bind to DetailsView? Here is what I have so far.
.aspx
<asp:GridView ID="GridView1" runat="server" AllowSorting="True" AllowPaging="True" PageSize="10" OnPageIndexChanging="countryGrid_PageIndexChanging"
CellPadding="4" ForeColor="#333333" Width="400px" Font-Size="9pt" [code].....
How to get data (read file) chosen in FileUpload control without FileUpload.SaveAs Method on the server? Is it possible write it at once to some object?
View 2 Replieshow can i link i file upload to a specific row in my gridi have item code column and for each row item code is not the same (no dupplicate)i want to upload excel sheet for each row in grid so how can i use FileUpload inside gridview using itemTemplate and linked it to rowId ??
View 2 Repliesi have a fileupload control in my asp.net application
when i click the control a dialogbox appears for selecting the file with open and cancel button
is it possible to capture the click event of this buttons & execute few code lines frm server side
Couple quick questions:What's the difference between FormView1_ItemUpdating and FormView1_OnUpdating? Do they occur at different times in the update process?Still can't get my code to upload the file...what am I missing?
View 9 RepliesI'm making a fairly simple online database where a user can upload a PDF file, along with 4 other data fields to a SQL DB. I have it working ok, sending the PDF to the DB as binary data. The problem is I would like to use a ListView control for the user to enter all of their data and choose the file to upload. When I use a ListView I receive the following error:
No mapping exists from object type System.Web.HttpInputStream to a known managed provider native type.
I've included the code I'm using to send the file to the DB (protected void ListView1_ItemInserting),
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I have two fileupload controls in footer of gridview with their corresponding checkboxes.
The autopostback property is set to true for both the checkboxes. Now after uploading file on one fileupload when i check the second checkbox, it detains(losses) its value.
How can i retain the value of first fileupload control on postback
I've been searching on this question for hours and not finding a solutionI simply want to access a FileUpload control in the EditItemTemplate of a FormView.When the FileUpload control is outside of the FormView, I can access it like this:
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Visual Studio says:"The name 'UploadImage1' does not exist in the current context" It says this about any controls I've put in the FormView.How do I access these controls in my c# code behind?
I would like to find controls in the detailsview control placed in the EmptyData Template of the gridview. I am trying to create Insert new record for the gridview control.
1. If there are existing records in the table - works fine and sets my two values: I placed Detailsview and Insert Button in the footer of the gridview. I needed to set the values of two fields. When I click on the Insert button it saves new record and sets the field with the value (code attached - works fine). I also have a popup extender that opens detailsview - this works just fine.
2, If ther are not records in the table - saves record but cannot find and set controls on the detailsview Same thing setup in the EmptyData Template. The record is saved but I cannot Find and set the field value on the control.
1. Link button (on click) in the gridview footer (works fine)
protected void LinkButton1_Click1(object sender, EventArgs e)
{
string zupa1;
zupa1 = ddlSelectEmployee.SelectedValue;
try
{
DetailsView zupa = (DetailsView)gvTraining4.FooterRow.FindControl("DetailsView1"); TextBox zupa2 = (TextBox) zupa.FindControl("txtInsertEmployee");
zupa2.Text = zupa1;
}
catch
{
}
DetailsView dettraining = (DetailsView)gvTraining4.FooterRow.FindControl("DetailsView1");
TextBox training = (TextBox) dettraining.FindControl("txtTrainingType");
training.Text = "4";
}
2. EmptyDataTemplate.FindControl - can save record but cannot access txtInsertEmployee and txtTrainingType
DetailsView zupa = (DetailsView)gvTraining4.EmptyDataTemplate.FindControl("DetailsView1");TextBox
zupa2 = (TextBox)zupa.FindControl("txtInsertEmployee");TextBox
training = (TextBox)dettraining.FindControl("txtTrainingType");"4";
I load a file using the FileUpload Control but it say I don't have a file? Please my code what am I doing wrong. Am I forgetting something.
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I have a FormView with a FileUpload to upload an image in a database.
I keep getting an object reference error.(view code)
I am using this same script to upload the image to the database, but when I try to update the file upload I get the error.
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I have a gridview with edit field. It has a footer row for insertion functionality. Now i also have a fileupload control in footer for uploading files on server. The url of files are stored in sql server2005. Now i have a fileupload control in <edititemtemplate> of gridview which can be used for uploading files while updating of gridview.
Now my req is whenever i upload file with fileupload control in <edititemtemplate> it should update the url of corresponding file in sqlserver2005. My query for update in sqldatasource is-
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Here draw_url is url field for my uploaded files.
How can i achieve the above functionality
I have four controls in my page: FileUpload, LinkButton, GridView, and Button.
FileUpload - I use the control to browse and open an Excel file in the client machine.
LinkButton - I use the control to trigger the method that copies the Excel file to the server, converts the data of Excel file to DataTable, deletes the Excel file, and returns the DataTable.
GridView - I use the control to display the data.
Button - I use the control to save the data to the database.
I did not see any problem until I uploaded the third file that hanged my page. I noticed that every time I upload a file, the page become slower gradually.
Each Excel file has 2,000 records, and every time the GridView displays an item, it searches the data on the database. I think, the more the data in the database, the slower the searches can be.
I set the AllowPaging property of GridView to true. The less displaying of items, the less searching of data can be. But, every time I change the page of GridView, I have to bind again the data to the GridView. In order to bind the data, FileUpload must contain the source file, but not because FileUpload frees the file when the page posts back. And I don't want the user browses the file every time he changes the page of GridView.
I've been looking around and trying a lot of different tactics to solve this issue but basically the senario is this.I have a gridview with a fileUpload in it.I can upload a file perfectly and it writes to the database.The trouble starts when I update a different cell and don't touch the cell with the fileUpload in it,it'll postback a null value to the database.
How can I keep the fileUpload control from sending a null on postback to the database so it won't clear out my entry if there isn't a new one to replace it?Or alternatively,how to I default the value to the old value on postback if nothing was entered through the FileUPload control?
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First of all, I'm relatively new to asp.net (3.5) and all of its controls. What I'm trying to do is to split up a detailsview. I have a submission form containing quite a lot of fields that are supposed to be filled out by the user. In my design I have a tabstrip with headlines about the different sections of the form. For example:
Tab1: Personal Info
Tab2: Info about your car
Tab3: Contact info
I have tested to add a new "user" via a DetailsView and it works. But what I want to do is to split up the contents within the <Field> tags In the DetailsView In different div classes (using css and javascript to hide/show the right tab contents). But when I try to do this Visual Studio says that characters like <p> and others aren't allowed within the Field tags, which makes sense. Is there any control to use for these kinds of situations?
i want to bind the existing value in database to dropdown list in dititemtemplate
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I need to test less than value of a integer value contained in a DetailsView
if ( DetailsView1.Rows[0].Cells[1] < 30 )
{
TextBox1.Visible = true;
}
getting error saying Operator '<' can't be applied to operands of type.TableCell' and int What am I missing? How does this differ from a GridView container?
What I'm trynna do is to input value in the TextBox1, and pass the string value to the label when button "ChangeText" is clicked.Pretty straightforward.
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and how to use both of those checkbox (for example: when i click update in my detailsview, if the checkbox is checked will return 1 and if unchecked will return 0 and insert that value to database)
I have a detailsview which is used to input data into an SQL database. Some of the fields contain drop down menus which are populated from the database.
I also have a form that allows the user to select mutiple values from a listbox (populated from an sql database) by moving the required items from one list box containing all the available items into a second one containing the selected items. There is also a text box which is used to filter on the available items. When this is passed through to a stored procedure to be put into the database, it is passed as a comma delimited string containing all the selected values.
This works fine on a separate form, however I would like to include it in one of the fields of the detailsview. This creates a BC30451: Name 'ListBox1' is not declared error. I have looked for hours on the internet to try and resolve this but cannot find what I need for how to declare the list for use within the detailsview.
Here is the code for both the working multiselect form and the code for when I have tried to integrate it into the detailsview:
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Multi-Select (CodeBehind):
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DetailsViewForm:
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DetailsView (CodeBehind):
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i have a problem with detailsview as below, when user click on btnEdit, it will call detailsview.changemode(edit) and then allow user to enter data into the textbox, after that user will click on btnsave and then to read the value from txtname and process the value. my question is how do i get the value from txtname? i dont want to use any datasource component and i have tried call the DetailsView1.FindControl("txtname") and it returned txtbox with empty text.
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