Forms Data Controls :: GridView Paging / Highlight The Actual Number Of Page?
Jan 3, 2010is there any way how to highlight the actual number of page where I am ? .... somethink like this: < 1 2 3 4 5
6 7 8 >
is there any way how to highlight the actual number of page where I am ? .... somethink like this: < 1 2 3 4 5
6 7 8 >
I want to display the paging format like 1 2 3 4 5 ....... 20 in gridview pagnation
here total number of pages count is 20.
if user clicks on the 20,then the page no 20 will be display..
and the user cilcks on .....,the next five pages has to display with last page number like 6 7 8 9 10 ....... 20
So my problem is as followes:
i have a gridview in another gridview (gv2 inside gv1).
in codebehind, at pageload i have: [Code]....
witch gives me a number of total records in the gv2 to a label. something like a coment number label.
my problem occures when i press the page button (allowpaging = true) on the first gridview. it acts kinda like this:
it makes the second gridview.visible = true; doest string the number of rows, and the label.text = "";
i've tried to make a code like this:
if (Ispostback)
{
gridview1.databind();
foreach ...etc..
}
else
{
foreach ....etc...
}
Also the gridview 1 and 2 the datasource is an SqlDataSource.
but that didnt work . also tried some things in pageindexchanged and pageindexchanging but still no efect :(. and also tried with enableviewstate = false / true on both gridviews with diferent combinations, but still no luck.
the code works only when i have allowpaging = false, or when im on the first page of the gridview (for the first time) is that the number of coments is pasted into the label.
<PagerStyle HorizontalAlign="Right" CssClass="paging"/>
<PagerTemplate>
<table width="100%">
<tr>
<td style="text-align:left; width:50%">
<asp:LinkButton ID="lnkPrv" Visible="false" CommandName="Page" CommandArgument="Prev" runat="server">Previous</asp:LinkButton>
</td>
<td style="text-align:right; width:50%;padding-left:50%;">
<asp:LinkButton ID="lnkNext" CommandName="Page" CommandArgument="Next" runat="server">Next</asp:LinkButton>
</td>
</tr>
</table>
</PagerTemplate>
Code behind is below
protected void gvProduct_PageIndexChanging(object sender, GridViewPageEventArgs e)
{
Literal1.Visible = gvProduct.PageIndex == 0;
LinkButton lnkPrv = (LinkButton)gvProduct.BottomPagerRow.FindControl("lnkPrv");
LinkButton lnkNext = (LinkButton)gvProduct.BottomPagerRow.FindControl("lnkNext");
lnkPrv.Visible = e.NewPageIndex > 0;
lnkNext.Visible = e.NewPageIndex < gvProduct.PageCount - 1;
gvProduct.PageIndex = e.NewPageIndex;
FillGrid();
}
The code does not give any error. I can see it set the visible property to true/false. But actual control on page remain same (always visible on every page).
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[Code]....
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[Code]....
Behind code:
[Code]....
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[Code]....
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<asp:GridView ID="GridView1" runat="server" AllowPaging="True"
AllowSorting="True" AutoGenerateColumns="False" DataKeyNames="NumofPosts"
DataSourceID="SqlDataSource1" [code]......
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HMTL:
<asp:Content ID="Content1" ContentPlaceHolderID="head" Runat="Server">
<%--style & Script for progress bar in Gridview --%>
<script type="text/javascript" src="//code.jquery.com/jquery-1.10.2.js"></script>
<script type="text/javascript" src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<link href="css/jquery-ui.css" rel="stylesheet" />
[Code] ....
C#:
protected void Page_Load(object sender, EventArgs e) {
if (!this.IsPostBack) {
BindGrid();
} }
protected void BindGrid() {
string query = "SELECT * FROM Table";
[Code] ....
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[Code]....
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[code]....
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[Code]....
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foreach (GridViewRow data in grid.Rows)
{
//here is my code
}
[URL]
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