MVC3 Razor - How To Conditionally Quit / End / Return Or Break A Partial View
Feb 15, 2011With Razor, how do you conditionally quit or end or return or break a partial view?
@if (Model == null)
{
return;
}
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[Code]....
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This is how I am submitting the form:
[Code]...
My Questions
The only thing I can think to do is return JSON from my controller with a flag indicating the state of the ModelState.IsValid and the corresponding partial that I should show.
1) How would I do this?
2) Is there a better way?
Update
I found this: [URL]
but it seems more likely that I am going about the whole thing incorrectly.
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[code]...
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[code]....
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[Code]....
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Update:
The reason for not using a section, RenderPartial or RenderaActions is to prevent the same stylesheet or script file to be added more than once to the Layout file.
The site im building has a Layout_.cshtml with the basic layout. This in turn is used by a View that loops through a list of items and for each item a RenderAction is called that outputs the specific partial view for that item. These partial views sometimes need to add stylesheets and scripts.
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Update 2:
The real question is how to do the same kind of function (a global list) but without using a static Extension method.
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