Return Part Of The Current Url?
Jan 3, 2011
HOw can i capture the second part of the url:For example:
http://www.yahoo.com/News/tezst/result.aspx
Should return:http://www.yahoo.com/News/
==================
http://www.yahoo.com/entertainment/default.aspx
Should return:
http://www.yahoo.com/entertainment/
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Jan 3, 2011
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[Code]....
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(any code snippets in VB, please).
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