Two Button Columns On A GridView Control?
Jun 16, 2010
I have a grid view will two different button columns. I want to perform a different action depending on what button the user presses. How in the SelectedIndexChanged event do I determine what colmun was pressed. This is the code I use to generate the columns.
grdAttachments.Columns.Clear();
ButtonField bfSelect = new ButtonField();
bfSelect.HeaderText = "View";
bfSelect.ButtonType = ButtonType.Link;
bfSelect.CommandName = "Select";
bfSelect.Text = "View";
ButtonField bfLink = new ButtonField();
bfLink.HeaderText = "Link/Unlink";
bfLink.ButtonType = ButtonType.Link;
bfLink.CommandName = "Select";
bfLink.Text = "Link";
grdAttachments.Columns.Add(bfSelect);
grdAttachments.Columns.Add(bfLink);
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Here's my radiobuttonlist:
<asp:RadioButtonList ID="Pending" runat="server" AutoPostBack="True" OnSelectedIndexChanged="Populategrid">
<asp:ListItem Value="250">Over 250</asp:ListItem>
<asp:ListItem Value="300">Over 300</asp:ListItem>
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Private Sub GridView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles GridView1.DataBound
GridView1.Columns(2).Visible = False
GridView1.Columns(3).Visible = False
GridView1.Columns(4).Visible = False End Sub
This is the code behind:
Protected Sub PopulateGrid(ByVal sender As Object, ByVal e As EventArgs)
'Select Case Pending.SelectedItem.Value ' Case "300"
Dim conn As New Data.SqlClient.SqlConnection(ConfigurationManager.ConnectionStrings("PendingClaimsConnectionString").ConnectionString)
Dim cmd As New Data.SqlClient.SqlCommand
[code]...
I'm getting an error under the If pending.selected value = "300" and .Parameters.AddWithValue etc...saying operator AND is not defined for types Boolean
Private Sub GridView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles GridView1.DataBound
GridView1.Columns(2).Visible = False
GridView1.Columns(3).Visible = False
GridView1.Columns(4).Visible = False End Sub0
[code]....
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Oct 21, 2015
[URL]
by using above thread its working great..
i want below rows and columns pattern
Rows 3, Columns 4 in my query..
1 2 3 4 -- Header
A 1 2 3 4
B 1 2 3 4
C 1 2 3 4
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Here is my code
[Code]...
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[Code] ....
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Feb 24, 2011
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Nov 8, 2010
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<asp:Button ID="btnSearch" runat="server" CausesValidation="True" CommandName="Search" Text="Search" ValidationGroup="vldSearch" /><br />
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If this is not the case, what is the best way to get a reference to the button control in the header row of the grid view?
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Jun 18, 2010
i wanna to add 2 button at the gridview control
@ when i click the button (tat is check in @ the check out) on the gridview
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got 2 problem
1 is how to do the button
2 is how to save the date @ the time (display the current date @ time when the moment v click the button) into database?
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Apr 8, 2013
I have grid view in my page below is my code
<asp:TemplateField ItemStyle-Width = "100px" ItemStyle-HorizontalAlign="Center">
<ItemTemplate>
<asp:Label ID="lblmob" runat="server" Text='<%# Eval("Tell")%>' CssClass="lblmobV"></asp:Label>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField ItemStyle-Width = "15px" ItemStyle-HorizontalAlign="Center">
<ItemTemplate>
[code]....
I want when users click on Linkbutton it insert data from gridview into Variz Table in database but when I click on link button below error happen Server Error in '/behtop website' Application. Object reference not set to an instance of an object. An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception System .NullReferenceException: Object reference not set to an instance of an object.Source Error:
Line 377: SqlCommand cmd = new SqlCommand("insertvariz", _cn); Line 378: cmd.CommandType = CommandType.StoredProcedure; Line 379: string Mobile = ((Label)GridView1.FindControl("lblMob")).Text; Line 380: Line 381: cmd.Parameters.Add("@ID", SqlDbType.VarChar).Value = lnkRemove2.CommandArgument;
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