Web Forms :: Toggle Or Switch Back And Forth Between Two Views?

Aug 5, 2010

I want to do is have a Multi view control on my form with two views that toggle between each other. When I click on a button on each view (Like a Next Button) I want the view to show the other view or to redisplay itself. I keep getting an error saying that the index is out of range.

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I have two application one is my mail application and from that mail on click on some link users goes to web browser. now i have added "Go back to your mail" link over there.and i have treid with Javafunction and window.open to switch the window to mail application. but it is not wroking with Tab brwoser.Now i want a function/code which perform like Alt+Tab to swtich to back on mail applicaiton from that browser - on click event. is there any way to do it in Asp.net.

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I am using Html.RenderAction<CartController>(c => c.Show()); on my master Page to display the cart for all pages. The problem is when I add an item to the cart and then hit the browser back button. It shows the old cart (from Cache) until I hit the refresh button or navigate to another page.

I've tried this and it works perfectly but it disables the Cache globally for the whole page an for all pages in my site (since this Action method is used on the master page). I need to enable cache for several other partial views (action methods) for performance reasons.

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If I had an e commerce website and wanted to toggle certain controls on or off through a check box or other control that resides on say an admin back end page, how would i go about doing that in C#?

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I am using a toggle button and when a button is clicked, the CSSclass is changed by checkign whether it is a 1 or 0. if it is a 1(on) , it will be set to 0, if it is a 0, it will be set to a 1.

Only 1 postback occurs on each click , and thats how a button is toggled on or off. In Internet explorer, this is working great. However, in FireFox and in Google Chrome, something odd is happening! When I click teh buttons, it is causing a double-postback.

This double-postback cancels out the first postback which was to turn on the button.

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Web Forms :: Toggle LinkButton In A GridView With A Loop

Jul 29, 2012

I am using GridView to display a list of forms submitted by a user and in one of the column I have a LinkButton which has got a conditional logic behind it to either display or hide it. The pseudo code for logic basically goes like this:If User has received a comment    Show the link to the comment on the GridView. Else     Hide LinkThis is the SQL that checks whether the user has got a comment for each submitted form:

Sql = "SELECT * FROM TableStudent INNER JOIN TableComment ON TableStudent .sID= TableComment .sID WHERE TableStudent .sID=@sID"
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For Each row As GridViewRow In gv1.Rows  If ds.Tables(0).Rows.Count = 0 Then     TryCast(gv1.Rows(0).FindControl("lnkBtnComment").FindControl("lnkBtnComment"), LinkButton).Visible = False  Else     TryCast(gv1.Rows(0).FindControl("lnkBtnComment").FindControl("lnkBtnComment"), LinkButton).Visible = True  End IfNext

I revised the code as it seemed to be affecting only the first column and changed it to this:

For Each gvrow As GridViewRow In gv1.Rows                If ds.Tables(0).Rows.Count = 0 Then                    TryCast(gvrow.FindControl("lnkDisplayComment"), LinkButton).Visible = False                    Response.Write(ds.Tables(0).Rows.Count)                Else                    TryCast(gvrow.FindControl("lnkDisplayComment"), LinkButton).Visible = True                    Response.Write(ds.Tables(0).Rows.Count)                End IfNext

Now the output for this has been if the associated form has any comment, it shows all the links and if the associated form has no comment, the comment links are hidden. And I have one applicant with two forms submitted; one of them has comment and the other does not. But my repsonse.write is returning 1 for both rows when I should clearly be 0 as it does not have any associated comment.

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I'm planning out a new website, using a master page. Now the site calls for two different layouts throughout. The home page will have a big image slider in jQuery. It's almost like a landing page. All other pages in my site will be without this slider, and will just have a bar with a heading on it.

Now my question is, can I use the same master page for both layouts by setting up certian areas of that master page into Panels that I can toggle the visibility on? The HTML is modular, so technically I can surround the slider div with a panel and depending on the visibility property, display it.

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I have an MVC view that contains a number of partial views. These partial views are populated using partial requests so the controller for the view itself doesn't pass any data to them. Is it possible to reload the data in one of those partial views if an action was triggered in another? For example, one partial view has a jqGrid and I want to refresh the data in another partial view when a user selects a new row in this grid. Is there a code example for this scenario (in C#) that I can look at to see what am I doing wrong? I am using ajax calls to trigger a new request but non of the partial views are refreshed so I am not sure if the issue is with the routing, the controller,

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IsDBNull(DataBinder.Eval(Container.DataItem, "expLeaflets")

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[Code]....

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[Code]....

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Using Vb.Net 2003 Asp.Net 1.1

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[Code]....

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[Code]....

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[Code]....

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[Code]....

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i m having problem with logout code in asp.net with c#. this logout code should end session, disable browser's back button and and if somebody try to login by paste the url of any user account page.i used this code in login page

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<asp:Button ID="Button2" runat="server" CausesValidation="False" OnClientClick="javascript:history.go(-3);return false;" Text="Back" UseSubmitBehavior="False" />

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When I click Logout page redirect to Login page but when click to browser arrow back then it will goes back, I want to after Logout cannot going to back page...

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[Code]....

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ASP Code:

===================================================================

Application #1

[Code]....

Application #2

[Code]....

Application #2

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