MVC :: View Model To Convert To Domain Model?
May 4, 2010
Say I got a domain model as follows: (and my repository expect an instance of this object)
[Code]....
And a view model (which my views are based on)
[Code]....
At the moment I got it like this and have my controller action manually create a new Person object from the PersonModel object before passing it on to the repository, which does not feel right.
So I tried to have PersonModel inherit from Person and pass that to the repository (also tried casting the PersonModel to a Person object first), but that don't work out.
What's the right way to have PersonModel automatically cast to Person? I want to keep this logic as my current structure allow me to keep things really loosely coupled, with the repository layer not having a clue how it's being used.
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[code]...
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Jun 2, 2010
I have been reading about different model for development
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[code]....
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Jun 28, 2010
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Sep 1, 2010
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Jan 10, 2011
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Mar 11, 2010
I have an issue of static variable in an asp.net application. Let's say I have a server with 8 CPUs running windows 2008 R2 hosting an asp.net webbsite, nothing fancy here, no funny configuration.
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Dec 28, 2010
I am trying to make a post that should use the Default Model Binder functionality in ASP.NET MVC 2 but unfortunately I can't get through. When I click on the checkout button I populate a form dinamically using jQuery code and then submit this form to the server. This is the form that get submitted
<form action="/x/Order/Checkout" id="cartForm" method="post">
<input name="__RequestVerificationToken" type="hidden" value="UDjN9RdWheKyWK5Q71MvXAbbDNel6buJd5Pamp/jx39InuyYIQVptcEubIA2W8DMUzWwnZjSGkLspkmDPbsIxy8EVuLvfCSZJJnl/NrooreouptwM/PaBEz2v6ZjO3I26IKRGZPqLxGGfITYqlf8Ow==">
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<input type="hidden" name="CartItems[1].ServiceTypeID" value="2">
<input type="hidden" name="CartItems[1].Quantity" value="1">
</form>
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$("#cartForm").submit(function (event) {
event.preventDefault(); var form = $("#cartForm");
var panel = form.parent(); panel.parent().block();
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async: false, data: form.serialize(),
success: function (response, status, xml) { panel.parent().unblock(); },
error: function (response) { panel.parent().unblock(); } }); });
This is the controller action that should be get called
[HttpPost]
[ValidateAntiForgeryToken]
public virtual ActionResult Checkout( CartModel cart ) {
} And finally this is the CartModel class involved
public class CartModel : BaseModel{
public int CustomerID { get; set; }
public int FirmID { get; set; }
public List<CartItemModel> CartItems { get; set; }
public CartModel() { CartItems = new List<CartItemModel>();
} } public class CartItemModel : BaseModel
{ public int ServiceTypeID { get; set; }
public int Quantity { get; set; } }
But the default Model Binder does not bind the web form data to a CartModel class. Using Fiddler I have been able to see that the data sent to the server is correct as you can see from the following snapshot.
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Aug 2, 2010
when I use Html.HiddenFor( model => model.OwnerId ) to create a hidden field, the value assigned to that field is zero. When I use <input type="hidden" value="<%: Model.OwnerId %>" /> to add the hidden field to the form, the value is assigned correctly.
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[Code]....
The Create action method is relatively straight forward.
public ActionResult Create( ... )
{
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Mar 15, 2011
I have an entity object as model input in my view. Not sure if it's the best approach, but I use the object references to get values from a related object.Let's say I've got a car entity and a manufacturer entity.Here's how it would look in my view
[Code]....
I've get a nullreferenceexception where the car entitity does not have a reference towards manufacturer. I'd like to output a " " if no manufacturer exists.
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Dec 29, 2010
've created a Search partial view and it works, except for my view model. What i mean is, the partial view sends a string to my ActionResult Method, but only a string, that is not related to the view model that the partial view is built in. If i tell my ActionResult method to receive the view model in which the partial view is built in, it always tells me that i have null values. Here's my code This is my partial view:
[Code]....
Now here is my Model in my MoviesSearch view model:
[Code]....
Now the actual MoviesSearchViewModel
[Code]....
Inside my Search controller i have this
[Code]....
And then i have this:
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Aug 26, 2010
one thing that has been puzzling me since learning MVC2 is the following case scenario: I have a view which contains two latest news lists, a login form and a signup form. Every example I found on Views and View Models so far has a one-to-one example such as a simple login form etc. But how do I create a model that provides the properties and validation for a login and signup form and manages the data for the news lists. can I pass multiple models in the strongly typed view? When I created one model the form validation would fail as it expects all fields - login and signup to be filled. I am missing some advanced examples or information.
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May 3, 2010
making my first steps with asp.net mvc and I actually create a (very) small website.I have 1 controller : TasksController1 view : Tasks/Index.aspx1 Partial View : Tasks/AvailableSorting.ascx In my controller I have 2 methods :
[Code]....
In my Tasks/Index.aspx, I add my partial view (<% Html.RenderPartial("AvaliableSorting"); %>)
That sounds simple. But, It just doesn't work : the Index return a list of Task and the parial view (should) return a list of string.The index.aspx works perfectly, but the partial view doesn't get the right model ! he gets the model of the Index page (list of Task).
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Nov 22, 2010
I would like to add a partial view to my view page
The view page contain a mode name "<IEnumerable<JvTake1.Models.VortN>>
And the partial view contain a model name "<IEnumerable<JvTake1.Models.VideoL>>"
So, theoretically I think they were suppose to work together but no Can any one guide me how to make it happen?
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Aug 6, 2010
I've got problem with my app .
I've got such classes (this is some kind of tree structure):
[Code]....
[Code]....
in Index() action i've got this piece of code
[Code]....
[Code]....
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Oct 27, 2010
I am totally a new bee in asp.net mvc. Let me now explain my issue. I have a strongly typed view which inherits from a view model Document. I want to have a partial view in that view itself. My code for this purpose is :
<%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<HexsolveMVC.Models.Document>" %>
<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
DetailsDocumentTemplate
</asp:Content>
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">
<div>
<div>
<div>
2.4</div>
<div>
Published</div>
<h1>
Document Title: <span>
<%=Model.DocTitle %></span><span><a href="#">[ Edit ]</a></span></h1>
<ul>
<li>
<label>
<span>*</span>Created Date:</label>
<span>
<%= Model.DocCreatedDate%></span></li>
<li>
<label>
Status:</label>
<span>.................................
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Jan 24, 2011
I have 3 table:
student: ID,name,family
course: ID,name
studentCourse: ID,studentID,CourseID
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which model should I use to create the view?I used viewModel but I don't know how to show this dropdownlist?
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Aug 4, 2010
can I do something like this to get the Mode.check value in my view..
<script type="text/javascript">
var check = <%(Model.Check); %>;
$(document).ready(function () {
[code]...
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May 5, 2010
I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed.How do I do I pass the model to this strongly typed view?I tried something like
public ActionResult Test()
{
MyData = new Data();
MyData.One = 1;
return View("Test",MyData)
}
In my TestView
<% Html.RenderPartial("PartialView",Model); %>
This give me a stackoverflow exception. So I am not sure how to pass it on. Of course I don't want to make the test view strongly typed if possible as what happens if I had like 10 strongly typed partial views in that view I would need like some sort of wrapper.
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