Web Forms :: GridView With Button On Footer - Error On Button Click To Create New Row
Jan 10, 2014
I am using a web form in vs2010 and in my form am having a gridview with button on footer. I have written the code to create a new row while click the button. If I click the button i got the following error
"unable to cast object of type 'system.web.ui.webcontrols.textbox' to type 'mysite.textbox"....
Below is the button click code.
private void AddNewRow() {
int rowIndex = 0;
if (ViewState["CurrentTable"] != null) {
dtCurrentTable = (DataTable)ViewState["CurrentTable"];
DataRow drCurrentRow = null;
if (dtCurrentTable.Rows.Count > 0)
[Code] ....
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[URL]
by using above thread its working great..
i want below rows and columns pattern
Rows 3, Columns 4 in my query..
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Sep 7, 2010
[URL]
I have used the above grid view in my application ... Its working good, no problem.
Upon clicking the Addnewrowbutton, it uses to create a new row dynamically.
What i need is, new row should also be created dynamically, upon pressing enter key in the last textbox on a particular gird view row. User always can't go and click addnewrowbutton every time to create new row. Instead of it, user can press enter in the last textbox on a particular grid view row to create new row.
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Dim gvTownships As New GridView
'COLUMNS
Dim tmpCategory As New TemplateField
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tmpCategory.FooterTemplate = New cGridViewTemplate(DataControlRowType.Footer, "Calculation")
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Sub InstantiateIn(ByVal container As System.Web.UI.Control) _
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End If
Case Else
' Insert code to handle unexpected values.
End Select
End Sub
Private Sub btnCalculate_Clicked(ByVal sender As Object, ByVal e As EventArgs)
Try
Dim btnCalculate As Button = CType(sender, Button)
Dim gvRow As GridViewRow = CType(btnCalculate.NamingContainer, GridViewRow)
btnCalculate.CommandArgument = "Calculate"
Catch ex As Exception
End Try
End Sub
End Class
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