Web Forms :: Set Enter Key Button For Gridview Footer Template?

Sep 7, 2010

[URL]

I have used the above grid view in my application ... Its working good, no problem.

Upon clicking the Addnewrowbutton, it uses to create a new row dynamically.

What i need is, new row should also be created dynamically, upon pressing enter key in the last textbox on a particular gird view row. User always can't go and click addnewrowbutton every time to create new row. Instead of it, user can press enter in the last textbox on a particular grid view row to create new row.

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[Code]....

[Code]....

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Code creating columns
Dim gvTownships As New GridView
'COLUMNS
Dim tmpCategory As New TemplateField
tmpCategory.ItemTemplate = New cGridViewTemplate(DataControlRowType.DataRow, "Category")
tmpCategory.HeaderTemplate = New cGridViewTemplate(DataControlRowType.Header, "Category")
tmpCategory.FooterTemplate = New cGridViewTemplate(DataControlRowType.Footer, "Calculation")
'INFORMATION
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gvTownships.CssClass = "mGrid"
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gvTownships.HeaderStyle.CssClass = "mgrid"
gvTownships.HeaderStyle.Wrap = True
gvTownships.FooterStyle.CssClass = "mGridtf"
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Sub InstantiateIn(ByVal container As System.Web.UI.Control) _
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Case DataControlRowType.Footer
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container.Controls.Add(btnCalculate)
End If
Case Else
' Insert code to handle unexpected values.
End Select
End Sub
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Try
Dim btnCalculate As Button = CType(sender, Button)
Dim gvRow As GridViewRow = CType(btnCalculate.NamingContainer, GridViewRow)
btnCalculate.CommandArgument = "Calculate"
Catch ex As Exception
End Try
End Sub
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[code]...

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[Code] ....

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[Code]....

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[Code]....

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[Code]....

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[Code]....

[Code]....

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