JQuery Hide All Table Rows Which Contain A Hidden Field Matching A Value?

Apr 15, 2010

I have a table for which I'd like to filter rows based on whether or not they contain a hidden field matching a value.

I understand that the technique tends to be "show all rows", "filter the set", "show/hide that filtered set"

I have the following jquery but I'm aweful with filter and my filtered set seems to always contain no elements.

my table is the usual

<table>
<tr><td>header></td><td> </tr>
<tr>
<td>a visible cell</td><td><input type='hidden' id='big-asp.net-id' value='what-im-filtering-on' />
</td>
</tr>
</table>

My goal is to be able to match on tr who's descendent contains a hidden input containing either true or false.

this is how I've tried the selector (variations of this) and I'm not even testing for the value yet.

function OnFilterChanged(e){
//debugger;
var checkedVal = $("#filters input[type='radio']:checked").val();
var allRows = $("#match-grid-container .tabular-data tr");
if(checkedVal=="all"){......

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