Web Forms :: Click A Button Which Shows A Table
Apr 22, 2010When i click a button(button1) i want a table (Tblstats) to show.
View 9 RepliesWhen i click a button(button1) i want a table (Tblstats) to show.
View 9 RepliesI have a button (btn1) and a table(Table1).At the moment in the load of the page is: table1.visible =falseIve tried putting in the button: table1.visible but it comes up with the blue line attached to the error: "property access must assign to the property or use its value"
View 4 RepliesHow to fix the error in code..this code will always display msg box if user select ot nt slect the checkbox ..
but i want if user doesn't select any of the checkbox or forgot to select checkbox then msg box will ppear other wise redirect to other page ..
<form id="form1" runat="server">
<div>
asp:CheckBox ID="CheckBox1" runat="server" /> [code]....
I am experiencing is that when I try to populate a table on a online environment with the below code, the table is populated twice. With the same code the table is populated correctly on an offline/production environment and cannot understand why :
This is what I have:
The table is called Trips
Code Behind:
[Code]....
This is what I use in my .aspx page:
(removed for brevity...)
<script type="text/javascript">
since I am trying to find one googling but there is nothing apparently.
I add this code but textbox value show in empty in database .. On Button Click the GridView TextBox loose all data ..
public partial class keyexam2 : System.Web.UI.Page {
//SqlConnection con = new SqlConnection(@"Data Source=.SQLEXPRESS;AttachDbFilename=D:shubhangijayonlinepaperApp_DataQUIZ.MDF;Integrated Security=True;User Instance=True");
DataTable dt = new DataTable();
//DataRow row = dt.NewRow();
[CODE]..
I have a simple table called education. the person enters 2 values
1. university
2. year completed
I want to add to the grid (where he inserts the education and year) the button click (add more) where he adds several education and then saves it to the database under the same user.
I have a form that works just fine, problem is that if user leave form open for more than 20 30 min and then click a button on that form the browsers status line shows "Error in page", user then must refresh the page in order for the page function.
View 1 RepliesI am developing a web site to display some data that is inside a database. To do this I've created an ASPX web page that opens a connection to a database and retrieves the desired data. After that it populates an asp:table object dynamically.
The problem is that some of the fields that are retrieved from the database are too large to be displayed on the web page, so I decided to make a popup that would be able to display just the desired field.
To do this I've added a button to the asp:table so that when the user clicks it the popup would appear with the contents of the field. However what is happening is that when the user clicks on the button, the page just gets reloaded and the Click event handler is never called.
Below is the code in which I add the button to a TableCell, and the TableCell to the TableRow collection:
[Code]....
note that the popupHandler is a delegate to the function below. I am using it as a the Click event handler for testing purposes.
[Code]....
Also you should be aware that the table is only populated when the user clicks on a "Query" button inside the main ASPX web page, this means that I only populate the table after the PageLoad event has occurred.
I'm reading an invoice dataset and building a html table with checkboxes and textboxes in it, and I put that code in a postback = false block, then i got a button and a literal. The button click will loop through the html table checkboxes to calculate a total and assign it to the literal and display it. I got everything working except one thing, every time i click the button, the html table refreshes and lost all the value in textboxes....even though I put the html building block in the postback = false block,it seems like it still won't preserve the values in the textboxes once there's a button click...Anybody knows a solution to that? I want the textboxes keep what values are there.
Here is the code part:
[code]....
I'm needing to get the selected rows, based on checkboxes, to insert into a different table than that that the gridview is formed from. I've created an innerjoin datasource to try and solve this but, still having problems finding something that works. I also need it to insert based upon a button click not inside the gridview as I believe otherwise would only hamper the situation more.
View 7 Repliescode for inserting rows by button click on table or grid
View 5 RepliesI have a table with text box asking for Name and Address for reference. If need be, I would like the user to have the ability to add more and not be restricted to just one. How would I add a new table to a form by clicking on my "getMore" button?
<table style="width:50%;">
<tr>
<th colspan="2">Reference</th>
</tr>
<tr>
<td>Name</td>
<td><input id="txtRefName" type="text" /></td>
</tr>
<tr>
[Code]....
I have to start working in a project. this project is already done 80%. Now i have to do further work in this. i want to know on some button click what database operations are performed in our sql server.
View 3 RepliesI have this issue i have been looking at for a while and cant seem to figure it out. I have two ddl's on my page and a InsertCommand from sqldatasource. My InsertCommand is actually updating the foreign key of the two ddl's in another table. When i click on my button it shows two numbers instead of one. The challenging thing now is that i have
DDLName.Items.RemoveAT("itemName.SelectedIndex")
after the insert so it would not duplicate what i am updating. If i take this statement out of my code. it updates well as in showing the one record that was updated. if i put it back in there it shows two records where updated. I tested my sql statement and its working fine meaning it shows only one record is updating.
I am populating a DataSet with records and displaying first row values in various text boxes in a panel on a view of a webpage. The DataSet is populated on view_activate event. I would like to add a "next" button to the page that would populate the appropriate textbox.text value with the value from the next DataRow at the button's click event. I'm struggling with how to approach this.
View 5 Repliescreate a website, it shows the count of the table in C#?he webpage looks like below: Pending: 45
View 7 RepliesWhy does my aspnet_Applications table show two apps? Does anyone know why this would be and if it makes any difference?
View 4 RepliesI want to create a table on Oracle on a click event of a button on ASP.NET. My webpage need a dynamic structure of table creation on the back-end (which I have connected with Oracle database).Please suggest me how can I do this with ASP.NET application?
View 2 Repliesi created dynamically a table with in a function... this table is added to a panel. and this panel is in ajax updatepanel... statically i have given no of rows as 3, for that table... in page_load my table with 3 rows is created.... but i cannot identify this table in another button click event...
i wrote the code like this...
System.Web.UI.WebControls.Table table = (System.Web.UI.WebControls.Table)addrowpnl.FindControl("Table1");
here Table1 is my dynamic table id.....
<ASP:Repeater id="MyRepeater" OnItemDataBound="MRBound" runat="server">
<HeaderTemplate>
<Table width="100%" style="font: 10pt verdana">
<tr style="background-color:DFA894">
<th>
Status
</th>
</tr>
</HeaderTemplate>
<ItemTemplate>
<tr style="background-color:FFECD8">
<td>
<%#DataBinder.Eval(Container.DataItem, "Status")%>
</td>
</tr>
</ItemTemplate>
<FooterTemplate>
</table>
</FooterTemplate>
</ASP:Repeater>
I want to change the status in the table to word(eg. pending, reject, accept) instead of number(0,1,2),
but i dont know how to select the extra row and value.
i want to create database on single button click and create table on newly created database on second button click . I am using ASP.Net and c#.
View 1 Repliesupdate table when shows image?{solved!}
View 1 Replieshow to hyperlink the database table (which shows in gird view in next page)
View 4 RepliesHow to create a table in the code behind to display data from the database by creating a new table etc. How I could target existing HTML in my aspx file as opposed to creating a new table in the code behind?
View 1 RepliesI am facing problem with diplaying FileUpload control on my aspx page. The problem is that when I drag the control in design view, it is showing a bordered TextBox and a Browse button on it right side but when I run my application, the button becomes "Choose File" button and TextBox appears at the right side of the button instead of left side and also it does not have any border. When I select a file, it is only showing a file name instead of the complete path. let me know that how could I display this control the same way as it was displaying during design time? I am using below code to display the control.
<asp:FileUpload ID="FileUpload1" runat="server" Width="222px "/>