AJAX :: Showing A Control On Click Of Linkbutton Column Of Gridview (present Inside UpdatePanel)

Jan 8, 2010

I have put my gridView inside an UpdatePanel with Timer control for auto refresh.The gridView has a linkButton column which is bounded to referenceNo column from database.

On click of this link button i want a panel to get visible. This Panel contains details corresponding to the referenceNo shown in differnt controls (mostly texboxes). Do i necessarily need to put the panel inside the Update Panel.If not how do i do it?

I have tried putting panel outside UpdatePanel, but it doesn't show panel on clicking the linkbutton nor does the values are updated inside this panel (if panel's visibility is set to true by default for testing purpose).

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My problem

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}
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Any thing i am missing on ? How to make chart control stay on the page and not vanish. I tried making it visible again. The main page contains a chart control which comes and goes away and does not stay only if i comment out the reloading of these usercontrols it stays visible with values on the main page else goes away.

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[code]....

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[code]....

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Portions of the sanitized code appear below. The GridView actually appears on a page that contains 2 dropdown lists and 2 other GridViews. There is just one UpdatePanel on this page.

[Code]....

This is in the Code-Behind.

[Code]....

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[Code]....

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[Code]....

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[Code]....

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Below you can find my sample code

[Code]....

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[Code]....

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[Code]....

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[code]....

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[Code]....

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Asp.net Markup:

[Code]......

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Dim linkBtn As New LinkButton
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Answer: i make that in page_load, it seems to work

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