How To Do Design The Database Columns Or Handle The Click Event
May 14, 2010
I'm looking to create a survey with a Radio Button List and a submit button and then I want to store the result in a database. Not sure how to do design the database columns or handle the click event to write the survey answer to a database.
i am having 2 imagebuttons a gridview and a button. Now if i clicked on Image button i will show a grid. Now under button click i would like to capture which image button was clicked if 1st image button is clicked i would like to some values and if 2nd one is clicked i would like to show another
I am using the AJAX tab container. How to capture the click event of the tab,whether client side or server side,,Means suppose when i clikc on tab0,I want to execute the certain Code.how to handle the click event of the tab?
The user enter the  name,address,country,qualifiction,experience the user enter more than one qualification, and experience the add another button click will add another qualification, and experience...i am confused in designing the database  how to design the database for this . i am design this tables .
==employee table== Â Â Â Â Â Â Â Â Â Â ===Qualification== Â Â Â Â Â Â Â Â Â Â Â ==Experience===
 employee_id                  qualificatin-id                      Experience_Id  employee_name               University                      Company  employee_address             Degree                        Year-of-0experience  employee_qualification           End_Date                       employee-id employee_Experience           employee-id
I wanted to catch and handle the ListBox Double Click event and looked for some sort of mehtod to do this. In one of the articles i found the usage of;
I've created a custom control in ASP.NET for showing a pop-up message box. In my MessageBox class, I have a Content property as ITemplate like the following:
[PersistenceMode(PersistenceMode.InnerProperty)] [TemplateContainer(typeof(MessageBoxContent))] [TemplateInstance(TemplateInstance.Single)] public ITemplate Content { get; set; }
Even I set the the Content property's TemplateInstance to Single, I still can't have access to the Button control.
All I want to do is to handle the click event of the button. When I assign an event handler to the button control and run the project, it throws a NullReferenceException.
I have a LinkButton within a User Control and it has handled with:
Private Sub LoginLinkLinkButton_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles LoginLinkLinkButton.Click Response.Redirect("/", True) End Sub
On certain ASPX pages I would like to handle the click from the page's code behind, opposed to within the user control. How do I override the handle within the control from the parent's code behind page?
Update:
Based on the answer, I have the following no added to the User Control:
[code]....
The problem is determining the correct syntax for the if line because the above is invalid.
I have a blank user control (child) and during Page_Load i create some text boxes and a button. I also add an event to the button.
I then load that user control dynamically from a placeholder in another usercontrol (parent). Both controls are rendered correctly but when i click on the button, the event isnt fired. how to handle the event?
Child code:
[code].....
If i use the child control directy (ie without the parent the control) the click event is raised and handled nicely. But when i use the parent control, the debugger wont even hit a breakpoint inside UpdateButton_Click().
Using a listview control for the first time... I need a button for each item, and of course I need to handle the click event for the buttons... upon clicking a particular button I of course need to know which item the button is associated with so the appropriate action can be taken...
In VS, I can't select the button and see my list of available events in the properties window like is normally done for controls outside of templates like this... what do I need to do?
I am displaying one question & their 4 options per page. For that i have one label for question & radiobuttonlist for their answers.There is next button. after clicking next button i want to display another record. I have tried this with dataset with random function, but its not proper. values gets repeated. so i want first record to be display in pageload & after clicking next button next record should move till record exists. I want to move one record to another after clicking next button.
From a user perspective, I can list of users in a grid with some associated checkboxes. When I click on a checkbox, I want to update the database straight away. No buttons involved.
I am new to MVC.
I am trying to work out if I can do this by using a BeginForm that wraps around each checkbox. It appears not, but how can clicking on a checkbox cause a POST?
Or maybe I can use a JQuery click or change event on the Checkbox? But in a grid the id for the checkbox is repeated, and I cannot get it to work even with 1 row of data.
The code below does not work. If I can get it to work, I need to send an AJAX post to call the method on the controller with the Model.UserId and the checkbox value;
I've found posts about making a click event with jQuery for a button, however I need a little more then that. When any postback occurs on a page, I need to fire off a jQuery click event. Based on a condition, I want to continue processing (including running the server-side event code after the jQuery code), or, perform a redirect. I'm not quite sure how to go about this.
I have a databound repeater and in this repeater is an imageButton. How do I pass info from the database into the click event? For example, I've got the description, heading and price fields populating labels, but want the id to go into the imagebuttons click event in order to build a querystring.
So I followed Scot Mitchell's tutorial from asp.net/learn on adding a checkbox column to be able to select multiple entries and delete them with the click of a button. When I make my selection and click the button it works on the database end, as the desired entries are deleted. However, the entries remain on the page after it reloads. if I refresh the page it's updated properly but I'd like it to automatically update after the button is clicked.
Also, I tried his method for adding check/uncheck all buttons to the top of the gridview and they don't seem to be working either.
just a general design question that I'd like to hear some of your opinions on. I am designing a system for a client, and I'm using GridView' a lot. They need a lot of columns to be displayed in some of these, and I've had to resort to using a panel with a horizontal scrollbar. This presents some issues - keeping track of which row is which is difficult, even with alternating row colours, and it's generally pretty ugly.How have you dealt with these issues before?
I need to display data in gridview like this. here Budget01...budget12 : Year1 Budget13...budget24 : Year2 Budget25...budget36 : Year3 Budget37...budget48 : Year4 Budget49...budget60 : Year5
I want to insert data in to the database by click on button and input box appears.The data entered in input box must insert into the database site that can quickly descirbe me asp.net controls and advance properties , actuallly i had created lots sites in php. Now time for asp.net
In my user control I have gridview, and this grid is created programmatically, using Itemplate. In InstantiateIn methods I have this code.
Select Case _templateType Case ListItemType.Header Dim linkButton As New LinkButton [code]....
I want to wired up Click event to this LinkButton, and use this event in code behind.This is constructor of GridViewTemplate how implements ITemplate
Public Sub New(ByVal type As ListItemType, ByVal colname As String, Optional ByVal infoType As String = "") 'Stores the template type. _templateType = type 'Stores the column na [code]....
and i have this call from user control:bfield.ItemTemplate = New GridViewTemplate(ListItemType.Item, dt.Columns(col).ColumnName, "label")
where is Dim bfield As TemplateField = New TemplateField()